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3 years ago

What = 1 + 3/6? If it is right will mark the brainiest if wrong gets reported.

Mathematics

2 answers:

Dahasolnce [82]3 years ago

7 0

I think The answer is 3/2 sorry if it’s wrong :(

Sergeu [11.5K]3 years ago

4 0

Answer:

1 and ahalf, so 1 1/2

Step-by-step explanation:

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Another way to write 1/2

earnstyle [38]

½=0.5.................

3 0

4 years ago

Read 2 more answers

Solve the equations PLEASEE<br><br> -1=3x-2<br><br> -3x=9<br><br> -10=-5x

Ilia_Sergeevich [38]

Answers are in bold:

-1=3x-2

add 2 to both sides

-1+2=3x-2+2

1=3x

divide both sides by 3

1÷3=3x÷3

1/3=x

-3x=9

divide both sides by -3

-3x÷-3=9÷-3

x=-3

-10=-5x

divide both sides by -5

-10÷-5=-5x÷-5

2=x

I hope this is good enough:

6 0

3 years ago

Help me with question a please ! With full workings !

frosja888 [35]

A)

$\bf \textit{distance between 2 points}\\ \quad \\
\begin{array}{lllll}
&x_1&y_1&x_2&y_2\\
% (a,b)
Q&({{ 0}}\quad ,&{{ 2}})\quad 
% (c,d)
P&({{ 0.5}}\quad ,&{{ 0}})
\end{array}\qquad 
% distance value
d = \sqrt{({{ x_2}}-{{ x_1}})^2 + ({{ y_2}}-{{ y_1}})^2}$

$\bf QP=\sqrt{(0.5-0)^2+(0-2)^2}\implies QP=\sqrt{0.5^2+2^2}
\\\\\\
QP=\sqrt{\left( \frac{1}{2} \right)^2+4}\implies QP=\sqrt{ \frac{1^2}{2^2}+4}\implies QP=\sqrt{\frac{1}{4}+4}
\\\\\\
QP=\sqrt{\frac{17}{4}}\implies QP=\cfrac{\sqrt{17}}{\sqrt{4}}\implies QP=\cfrac{\sqrt{17}}{2}$

b)

since QR=QP, that means that QO is an angle bisector, and thus the segments it makes at the bottom of RO and OP, are also equal, thus RO=OP

thus, since the point P is 0.5 units away from the 0, point R is also 0.5 units away from 0 as well, however, is on the negative side, thus R (-0.5, 0)

c)

what's the equation of a line that passes through the points (-0.5, 0) and (0,2)?

$\bf \begin{array}{lllll}
&x_1&y_1&x_2&y_2\\
% (a,b)
Q&({{ 0}}\quad ,&{{ 2}})\quad 
% (c,d)
R&({{ -0.5}}\quad ,&{{ 0}})
\end{array}
\\\\\\
% slope = m
slope = {{ m}}= \cfrac{rise}{run} \implies 
\cfrac{{{ y_2}}-{{ y_1}}}{{{ x_2}}-{{ x_1}}}\implies \cfrac{0-2}{-0.5-0}\implies \cfrac{-2}{-0.5}$

$\bf m=\cfrac{\frac{-2}{1}}{-\frac{1}{2}}\implies \cfrac{-2}{1}\cdot \cfrac{2}{-1}\implies 4
\\\\\\
% point-slope intercept
y-{{ y_1}}={{ m}}(x-{{ x_1}})\implies y-2=4(x-0)\implies y=4x+2\\
\left. \qquad \right. \uparrow\\
\textit{point-slope form}$

7 0

3 years ago

A verbal description of a linear function f is given. Express the function f in the form

Lerok [7]

The linear function g which has a rate of change of -16 and initial value 600 is; g = -16x + 600.

<h3>What is the linear function which is as described?</h3>

It follows from the task content that the linear expression which is as described by the given verbal description is to be determined.

Since the standard slope-intercept form of a linear function is as given; f(x) = ax + b.

Where, a = slope (rate of change) and b = y-intercept (initial value).

Therefore, the required linear function which is as described is;

g = -16x + 600

Read more on linear functions;

brainly.com/question/15602982

#SPJ1

6 0

1 year ago

A need help Dilations-He Said, She Said (12/10)

Elodia [21]

Answer:

We conclude that the original triangle ΔDEF is dilated by a scale factor of 5/2 to get the image triangle ΔD'E'F'.

Therefore, 'Cárl' is correct. Hence, option 'a' is correct.

Step-by-step explanation:

Checking the location of the vertices of the original triangle ΔDEF

D(-2, 4)
E(2, 4)
F(0, 2)

Checking the location of the dilated vertices of the image triangle ΔD'E'F'

D'(-5, 10)
E'(5, 10)
F'(0, 5)

Notice that if we multiply the vertices of the original triangle ΔDEF by 5/2, we get the correct image vertices of image triangleΔD'E'F'

i.e.

D(-2, 4) → D'(5/2 (-2), 5/2 (4)) → D'(-5, 10)

E(2, 4) → E'(5/2 (2), 5/2(4)) → D'(5, 10)

F(0, 2) → E'(5/2 (0), 5/2(2)) → F'(0, 5)

Thus, we conclude that the original triangle ΔDEF is dilated by a scale factor of 5/2 to get the image triangle ΔD'E'F'.

Therefore, 'Cárl' is correct. Hence, option 'a' is correct.

6 0

3 years ago