For a normal distribution, the z value for an x value that is to the right of the mean is always:

1 answer:

7 0

In a normal distribution, the z value for an x value that is to the right of the mean will always be positive while on the other hand if the z value for an x value that is to the left of the mean it will always be negative. It is because left side is always negative and right side is always positive.

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Need help with this please

lana [24]

Answer:n

geadeeeeeeeeeee

Step-by-step explanation:

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2 years ago

Would anyone like to solve this problem for me?

dalvyx [7]

The answer would be 24 pints

7 0

3 years ago

ANSWER THIS STAT PLEASE & THANKS<br><img src="https://tex.z-dn.net/?f=%20%5Cfrac%7B5%7D%7B7%7D%20%20%5C%3A%20%20-%20%20%5Cfr

Brut [27]

$\frac{27}{24}$ or 1 $\frac{1}{8}$ is the answer

7 0

3 years ago

Find the sum of a finite geometric series. The Smiths spent $2,000 on clothes in a particular year. If they increase the amount

boyakko [2]

$\bf \stackrel{\textit{first year}}{2000}~~,~~\stackrel{\textit{second year}}{2000+\stackrel{\textit{10\% of 2000}}{\frac{2000}{10}}}\implies 2200$

now, if we take 2000 to be the 100%, what is 2200? well, 2200 is just 100% + 10%, namely 110%, and if we change that percent format to a decimal, we simply divide it by 100, thus $\bf 110\%\implies \cfrac{110}{100}\implies 1.1$ .

so, 1.1 is the decimal number we multiply a term to get the next term, namely 1.1 is the common ratio.

$\bf \qquad \qquad \textit{sum of a finite geometric sequence}\\\\S_n=\sum\limits_{i=1}^{n}\ a_1\cdot r^{i-1}\implies S_n=a_1\left( \cfrac{1-r^n}{1-r} \right)\quad \begin{cases}n=n^{th}\ term\\a_1=\textit{first term's value}\\r=\textit{common ratio}\\----------\\a_1=2000\\r=1.1\\n=4\end{cases}\\\\\\S_4=2000\left[ \cfrac{1-(1.1)^4}{1-1.1} \right]\implies S_4=2000\left(\cfrac{-0.4641}{-0.1} \right)\\\\\\S_4=2000(4.641)\implies S_4=9282$

7 0

3 years ago

WILL GIVE BRAINIEST!!!!!!

Veseljchak [2.6K]

Answer:

The answer is y = x

Hope this helps!

4 0

2 years ago