You add/sub all the h and all the regular numbers u will get the answer
Answer: 5 5h
Answer:
coordinates of A are (11/2, -3/2)
Step-by-step explanation:
midpoint = M(5, −4)
start point = A(6, 1)
endpoint = B(x, y)
equation :
x = m1 × x2 + m2 × x1 y = m1 × y2 + m2 × y1
_____________ _____________
m1 + m2 m1 + m2
x = (1 × 6) + (1 × 5) y= (1 × 1) + (1 × -4)
_____________ ____________
1 + 1 1 + 1
x = (6+5 )/ 2 = 11 / 2 y = (1+(-4))/2+(1-4)/2 = -3/2
∴coordinates of A are (11/2, -3/2)
i think u should view this on a wider screen if ur using a phone <3
Answer: The answer is 43.5 because when using the formula you get this result.
Step-by-step explanation: Area of triangle is base x height divided by 2. So do our base 14.5 and our height 6 and multiply them together. 14.5 x 6 = 87 / 2 = 43.5
Answer:
The linear model will give a good approximation if the new value is within or close to the values we used to construct the linear model.
Step-by-step explanation:
A linear model gives reasonable approximations under these two conditions:
- If the value for which we need to use the approximation is within the range of values we used to construct the linear model
- If the value for which we need to use the approximation is close to the values which we used to construct the linear model.
For the given model, heights of children aged 5 to 9 were recorded. Here, age is the independent variable and height will be the independent variable. Heights of 30 children from age 5 to 9 were recorded and a linear model was constructed. Now, we need to tell which value of age can be made an input of this function to find the approximate height.
Using the above two principles, the linear model will give a good approximate if:
- The age of the child is between 5 and 9 years. In this situation, the value approximated by the model will be closer to the actual height in majority of the cases. For example, the model will give good approximations for children of ages 6, 6.5, 7, 7.75 etc
- The age of child is close to 5 and 9 years old but outside the range. In this case, the model will also give good approximations. For example. for a child of age 4.5 years or 10 years, the model will still give a good and reasonable approximations.
Math assignment = 3/8 hours
History assignment = 1/4 hours
We can not compare this as both fractions do not have alike denominators.
We can fix this problem easily by turning 3/8 and 1/4 into alike denominator fractions.
We can turn 1/4 into 2/8 as it is equivalent fractions.
1 x 2 = 2
4 x 2 = 8
(Whatever you do to the denominator, you have to do the same to the numerator)
Once we get this, we can see that Shen spent 2/8 hours on his homework while he spent 3/8 hours on his math assignment.
3/8 - 2/8 = 1/8
1/8 = 0.125
Shen spent 1/8 of an hour (or 0.125 of an hour) more on his math assignment than his history assignment.
