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liraira [26]
3 years ago
12

4.06 = 0.19 = 0.29 = 0.86 = 19% 29% 38% 332% 247% 293% 2.98 = 406% 0.81 = 353% 2.93 = 22% 4.61 = 86% 6% 81% 483% 41% 422% 461% 3

.35 = 298% 0.68 = 68% FINISH 55% 0.38 = 424% 71% 413% 315% 26% 88% 92% 2.4 = 335% 0.74 = 74% 3.32 = 3.53 = 172% 248% 240% 125% 28%
Mathematics
1 answer:
dimulka [17.4K]3 years ago
3 0

Answer:

what are you asking though

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I need help with number 46 Thankyou
Over [174]
A²+B²=C²
6²+8²=C²
C²=100
C=10
Therefore the length of AB is 10 units
8 0
3 years ago
7<br><img src="https://tex.z-dn.net/?f=7%20%20%5E%7B2%7D%20-%20%20%7C6%20-%202%287%29%7C%20%5Ctimes%203%20%5E%7B2%7D%20" id="Tex
frutty [35]

Answer:

-23

Step-by-step explanation:

you calculate 49-|6-14|x 9

you then calculate the absolute value

49-|-8|x 9

then multiply the numbers

49-8 x 9

calculate those numbers

49 - 72

your solution will be -23

5 0
3 years ago
What is the perimeter of the rectangle shown below? apex algebra 1 sem 1 unit 6
Allushta [10]
Great job! you didn't include the rectangle! no one can answer this question! you're the best!
7 0
3 years ago
Read 2 more answers
PLEASE HELP ME RN PLEASE ​
Advocard [28]

Answer:

1.

\frac{n^{2} - 1 }{2}

2.

\sqrt{29}

Step-by-step explanation:

Area of triangle=1/2×b×h

=

\frac{1}{2}  \times (n - 1)(n + 1)

\frac{( {n}^{2} + n - n - 1) }{2 }

\frac{ {n}^{2} - 1 }{2}

2. Area of triangle=14

\frac{ {n}^{2} - 1 }{2}  = 14

{n}^{2}  - 1 = 28

{n}^{2}  = 29

n =  \sqrt{29}

please rate well and mark BRAINLIEST.

thanks

3 0
2 years ago
How do I solve question 6 through 8?<br> Solve for me
rewona [7]

The equations of the functions are y = -4(x + 1)^2 + 2, y = 2(x - 2)^2 + 1 and y = -(x - 1)^2 - 2

<h3>How to determine the functions?</h3>

A quadratic function is represented as:

y = a(x - h)^2 + k

<u>Question #6</u>

The vertex of the graph is

(h, k) = (-1, 2)

So, we have:

y = a(x + 1)^2 + 2

The graph pass through the f(0) = -2

So, we have:

-2 = a(0 + 1)^2 + 2

Evaluate the like terms

a = -4

Substitute a = -4 in y = a(x + 1)^2 + 2

y = -4(x + 1)^2 + 2

<u>Question #7</u>

The vertex of the graph is

(h, k) = (2, 1)

So, we have:

y = a(x - 2)^2 + 1

The graph pass through (1, 3)

So, we have:

3 = a(1 - 2)^2 + 1

Evaluate the like terms

a = 2

Substitute a = 2 in y = a(x - 2)^2 + 1

y = 2(x - 2)^2 + 1

<u>Question #8</u>

The vertex of the graph is

(h, k) = (1, -2)

So, we have:

y = a(x - 1)^2 - 2

The graph pass through (0, -3)

So, we have:

-3 = a(0 - 1)^2 - 2

Evaluate the like terms

a = -1

Substitute a = -1 in y = a(x - 1)^2 - 2

y = -(x - 1)^2 - 2

Hence, the equations of the functions are y = -4(x + 1)^2 + 2, y = 2(x - 2)^2 + 1 and y = -(x - 1)^2 - 2

Read more about parabola at:

brainly.com/question/1480401

#SPJ1

5 0
2 years ago
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