All categories

3 years ago

HELP! WHAT DO YOU DO WHEN YOU'RE ON PUNISHMENT? I made 2 C's and I'm on punishment!!!!

Mathematics

2 answers:

maksim [4K]3 years ago

6 0

Answer:

drop down like larry

Step-by-step explanation:

Marta_Voda [28]3 years ago

3 0

Answer:

c then a then b then d

Step-by-step explanation:

You should probably fix your grades, which will make you cry bc school is stressful (i keep tissues at my desk for this particular reason), which will probably make you drop down like larray, then you can slap karla so you feel better.

I hope this helped you! i also hope you get ungrounded soon!

You might be interested in

Silas and Lilly attended a math conference. The total registration fee was $327.50. If each person paid the same amount, which e

castortr0y [4]

Answer:I think the answer is letter B.

Step-by-step explanation:

8 0

3 years ago

Can someone help me answer this

VikaD [51]

C

Your welcome lolololololol

8 0

3 years ago

Read 2 more answers

100 POINTS AND BRAINLIEST

zysi [14]

Answer:

8 square units and $\frac{40}{3}$ square units

Step-by-step explanation:

The area of the triangle ABC is 24 square units.

1. Triangles ABC and FBG are similar with scale factor $\frac{1}{3},$ then

$\dfrac{A_{\triangle FBG}}{A_{\triangle ABC}}=\dfrac{1}{9}\Rightarrow A_{\triangle FBG}=\dfrac{1}{9}\cdot 24=\dfrac{8}{3}\ un^2.$

2. Triangles ABC and DBE are similar with scale factor $\frac{2}{3},$ then

$\dfrac{A_{\triangle DBE}}{A_{\triangle ABC}}=\dfrac{4}{9}\Rightarrow A_{\triangle DBE}=\dfrac{4}{9}\cdot 24=\dfrac{32}{3}\ un^2.$

3. Thus, the area of the quadrilateral DFGE is

$A_{DFGE}=A_{\triangle DBE}-A_{\triangle FBG}=\dfrac{32}{3}-\dfrac{8}{3}=8\ un^2.$

and the area of the quadrilateral ADEC is

$A_{ADEC}=A_{\triangle ABC}-A_{\triangle DBE}=24-\dfrac{32}{3}=\dfrac{40}{3}\ un^2.$

4 0

3 years ago

Read 2 more answers

It's all on the picture please answer it

zubka84 [21]

14?
17-12=5
5x2=10
10+4 =14

7 0

3 years ago

Read 2 more answers

Need help and will be giving Brainliest

Katena32 [7]

Answer:

x-intercept (s):

For this case h (x) = 0

x2 - 2x - 8 = 0

(x-4) * (x + 2) = 0

x1 = 4

x2 = -2

y-intercept:

For this case x = 0

h (0) = (0)2 - 2 (0) - 8

h (0) = - 8

vertex:

We derive the equation:

h '(x) = x2 - 2x - 8

h (x) = 2x - 2

We match zero:

2x-2 = 0

x = 2/2

x = 1

We evaluate the function for x = 1

h (1) = (1)2 - 2 (1) - 8

h (1) = 1 - 2 - 8

h (1) = -9

The vertex is:

(1, -9)

axis of symmetry of the function:

x = 1

Step-by-step explanation:

hope it helps

6 0

3 years ago