C and d are supplementary the measure of

Emanuel works as a car salesman. He makes $13 an hour plus a commission of 5% on all cars he sells. Last month he worked 40 hour

gtnhenbr [62]

Solution: Emanuel earns $13 per hour. Also he earns a commission of 5% on all cars he sells.

Number of hours Emanuel worked last month = 40 hours

He sold cars worth $120,000.

Therefore, the total earning of Emanuel is:

$13 \times 40 + 5\% of 120,000$

$520 + \frac{5}{100} \times 120,000$

$520+6000$

$6520$

Hence, last month Emanuel made $6520, including his hourly pay and commissions.

7 0

3 years ago

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What is the square root of 48 simplified?

ivanzaharov [21]

The square root of 48 simplified is 4 sqrt 3.

6 0

2 years ago

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The temperature in some region of Alaska equals 15 F. Convert this temperature to Celsius.

sergij07 [2.7K]

The formula you need to use is C = 5/9•(F - 32)

So take 15 and subtract 32: 15-32 = -17
Then multiply that by 5/9: 5/9•(-17) ≈ -9.44

7 0

3 years ago

Which products result in a difference of squares? Select three options. (x minus y)(y minus x) (6 minus y)(6 minus y) (3 + x z)(

ValentinkaMS [17]

Answer:

Third option: $(3 + xz)(-3 + xz)$

Fourth option: $(y^2 - xy)(y^2 + xy)$

Sixth option: $(64y^2 + x^2)(-x^2 + 64y^2)$

Step-by-step explanation:

By definition, we can factor the Difference between two squares:

$a^2 - b^2 = (a+b)(a-b)$

In order to find which products results in a difference of squares, we need to check each option:

$1.\ (x - y)(y - x)=(x)(y)+(x)(-x)-(y)(y)+(-y)(-x)=xy-x^2-y^2+xy=-x^2-y^2+2xy$

The product does not result in a difference of squares.

$2.\ (6 - y)(6 - y)$

Since the signs are equal ( $-$ ), the product will not result in a difference of squares.

Using Distributive Property for the other options, we get:

$3.\ (3 + xz)(-3 + xz)=(3)(-3)+(3)(xz)+(xz)(-3)+(xz)(xz)=\\\\=-9+3xz-3xz+x^2z^2=x^2z^2-9=(xz)^2-(3)^2$

The product results in a difference of squares.

$4.\ (y^2 - xy)(y^2 + xy)=(y^2)(y^2)+(y^2)(xy)-(xy)(y^2)-(xy)(xy)=\\\\=y^4+xy^3-xy^3-x^2y^2=y^4-x^2y^2=(y^2)^2-(xy)^2$

The product results in a difference of squares.

$5.\ (25x - 7y)(-7y + 25x)=(25x - 7y)(25x - 7y)$

Since the signs are equal ( $-$ ), the product will not result in a difference of squares.

$6.\ (64y^2 + x^2)(-x^2 + 64y^2)=(64y^2 + x^2)(64y^2 - x^2)=\\\\=(64y^2)(-x^2)+(64y^2)(64y^2)+(x^2)(-x^2)+(x^2)(64y^2)=\\\\=-64y^2x^2+4096y^4-x^4+64y^2x^2=\\\\=4096y^4-x^4=(64y^2)^2-(x^2)^2$

The product results in a difference of squares.

5 0

3 years ago

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on the first play of a game , a football team gained 23 yards and then lost 10 yards due to penalty during the second play the t

zepelin [54]

-1 Let's say the set of downs starts at the 20 yard line (maybe the kicking team kicked deep, the receiving team took a knee and so play starts at the 20).
Ok - we're at the 20. First down - they advance 5 yards. So we're now at the 25. We can write that mathematically as:
20
+
5
=
25
So the second play they get sacked deep and lose 6 yards. So we subtract 6:
25
−
6
=
19
So what's the change in yardage for the 2 plays? We are on the 19 and started at the 20, so we can write:
19
−
20
=
−
1
and this makes sense because we know we advanced 5 and fell back 6

3 0

3 years ago