Question

The expression 16t^2 represents the distance in feet the object falls after t seconds. The object is dropped from a height of 906 feet. What is the height in feet of the object 2 seconds after it is dropped?

Answer 1

Answer:842

Step-by-step explanation:

Answer 2

Answer:

824 feet

Step-by-step explanation:

Given

$h(t) = 16t^2$

$H = 906$ -- Initial Height

Required

Determine its height after 2 seconds

First, we calculate the distance covered in 2 seconds

$h(t) = 16t^2$

$h(2) = 16*2^2$

$h(2) = 16*4$

$h(2) = 64$

This means that the object moved a distance of 64feet

So, the object height is calculate by subtracting the distance covered from the object's initial height:

i.e.

$Height = H - h(2)$

$Height = 906- 64$

$Height = 824$