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2 years ago

Hello! Can anyone please tell me the measurement of t and v ? Any help is gladly appreciated.

Mathematics

1 answer:

s344n2d4d5 [400]2 years ago

7 0

Answer:

Step-by-step explanation:

is this 8th grade math?

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Slope of (1,5) and (3,12)

Dima020 [189]

The slope is 3.5, also known as 3 1/2.

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3 years ago

Which two complex numbers that could have been added together to make -11+3i

irina [24]

Answer:

Step-by-step explanation:

There are an infinite number of possible solutions.

here's a few

(1 - 4i) + (-12 + 4i)

(-5.5 + 2i) + (-5.5 + i)

(-24 - 27i) + (13 + 30i)

3 0

3 years ago

Please Help. 25 points. <br>

vodomira [7]

Answer:

$\boxed{x = 7, y = 9, z = 68}$

Step-by-step explanation:

We must develop three equations in three unknowns.

I will use these three:

$\begin{array}{lrcll}(1) & 8x + 13y +7 & = & 180 & \\(2)& 9x - 7 + 13y +7 & = & 180 & \\(3)& 8x + 5y - 11 + z & = & 180 &\text{We can rearrange these to get:}\\(4)& 8x + 13y & = & 173 &\\(5) & 9x + 13y & = & 180 & \\(6)& 8x + 5y + z & = & 169 & \\(7)& x & = & \mathbf{7} & \text{Subtracted (4) from (5)} \\\end{array}$

$\begin{array}{lrcll}& 8(7) + 13y & = & 173 & \text{Substituted (7) into (4)} \\& 56 + 13y & = & 173 & \text{Simplified} \\& 13y & = & 117 & \text{Subtracted 56 from each side} \\(8)& y & =& \mathbf{9}&\text{Divided each side by 13}\\& 8(7) + 5(9) + z & = & 169 & \text{Substituted (8) and (7) into (6)} \\& 56 + 45 + z& = & 169 & \text{Simplified} \\& 101 + z& = & 169 & \text{Simplified} \\&z& = & \mathbf{68} & \text{Subtracted 101 from each side}\\\end{array}$

$\boxed{\mathbf{ x = 7, y = 9, z = 68}}$

4 0

3 years ago

Write an equation in point-slope form for the line that passes through the point with the given slope.

Over [174]

Answer:

y=0x+6

Step-by-step explanation:

7 0

2 years ago

Find the interval(s) of upward concavity on this accumulation function.

maxonik [38]

$\displaystylef(x)=\int_{0}^{x^2}\sec^2(\sqrt{x})dx \\=\int_{0}^{\sqrt{x^2}}\sec^2(u)\cdot2udu \\=2\int_{0}^{\sqrt{x^2}}\sec^2(u)du \\=2\Big[u\tan(u)-\int\tan(u)du\Big]_{0}^{\sqrt{x^2}} \\=2\Big[u\tan(u)+\ln\Big(\mathrm{abs}(\cos(u))\Big)\Big]_0^x \\=2\Big(x\tan(x)+\dfrac{1}{2}\ln\Big(\cos^2(x)\Big)\Big) \\=2x\tan(x)+\ln(\cos^2(x))$

Hope this helps.

6 0

3 years ago

Hello! Can anyone please tell me the measurement of t and v ? Any help is gladly appreciated.​

Hello! Can anyone please tell me the measurement of t and v ? Any help is gladly appreciated.