Write it out as a set of equation:
Let x be number of 8 cent stamps, y be 10 cent stamps, and z be 2 cent stamps.
x=y
z=x+y
8x+10y+2z=440
Lets first solve for x:
from x=y and z=2x(from first equation) the last equation is
8x+10x+4x=440
22x=440
x=20
know that x=20, you also know that y=20 as well, since z=x+y, z=40.
So 20 8-cent stamps, 20 10-cent stamps, and 40 2-cent stamps.
Answer:
Y= -4 :)
Steps:
Apply rule
-y + 3 = 7
Subtract 3 from both sides
-y + 3 - 3 = 7 - 3
Simplify
-y = 4
Divide both sides by -1
-y/-1 = 4/-1
Simplify
y = -4
Answer:
x=0
Step-by-step explanation:
We are given:
g(x) =10x +2
and
g(x)=2
g(x) is equal to both 10x+2 and 2. Therefore, by substitution, we can set them equal to each other
10x+2=2
Now, we need to solve for x. First, move all the numbers to the same side. Subtract 2 from both sides
10x+2-2=2-2
10x=0
To solve for x, we have to get x by itself. x and 10 are being multiplied. To get x alone, divide both sides by 10.
10x/10=0/10
x=0
Answer:
£39.95
Step-by-step explanation:
multiply it by £7.99×5
Step-by-step explanation:
23. area of rect,r = 11 x 3.5 = 38.5cmsq
area of tri, t = 6 x3.5/2 = 10.5 cmsq
area of shaded region, sr = r-t
=> sr = 38.5- 10.5 = 28.5cmsq
24. area of square, s = 10x10 = 100mmsq
area of circle, c = pi x 5^2 = 78.5mmsq
area of shaded region, sr = s - c
=> sr = 100- 78.5 = 22.5mmsq
25. area of circle, c = pi x 6^2 = 113.04insq
area of tri, t = 6x12/2 = 36insq
area of shaded region, sr = c - t
=> sr = 113.04 - 36 = 77.04insq
