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JulsSmile [24]
3 years ago
11

2.83333333333 simplify

Mathematics
2 answers:
iVinArrow [24]3 years ago
7 0
Sorry but I don’t think you can simplify a repeating number all you can do is round it to 2.83:)
nirvana33 [79]3 years ago
4 0

Answer: So the answer is 2.83

Step-by-step explanation: This is a terminating decimal number, so if I round up to the nearest trillionth place it will be 2.83. Just only give me a thanks and 5-star rate. :)

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1) Slope =-1, y-intercept = 0
Dima020 [189]

Answer:

1. C       2.D       3.D        4.A

Step-by-step explanation:

The first one would be C because the slope is -1, which can also be -x and the y-intercept is 0, meaning you don't need to add or subtract anything.

The second one is D because the slope is -3, meaning it's -3x, and the y-intercept is positive, meaning you add 5.

The third one is D because the slope is 5/4, which is 5/4x and the y-intercept is positive 3, meaning you add 3.

And the fourth one is A because there is no slope, so y would just equal 3.

6 0
3 years ago
Explain the steps you would take to complete this conversion problem
OLEGan [10]

Answer:

20909.09 grams

Step-by-step explanation:

\frac{46 \: lb}{1}  \times  \frac{1 \: kg}{2.2 \: lb}   \times  \frac{1000 \: g}{1 \: kg}  = \\ \frac{46 \: lb}{2.2 \: lb}  \times  \frac{1 \: kg}{1} \:   \times  \frac{1000 \: g}{1 \: kg}  = \\\frac{230 \: }{11 \:}  \times \frac{1 \: kg}{1 \: kg \:}\times \frac{1000 \: g}{1 \:}  = \\\frac{230 \: }{11 \:}  \times \frac{1}{1}\times \frac{1000 \: g}{1 \:}  = \\\ \frac{230}{11}g  \times 1g  \times \: 1000g

= 230 grams / 11 grams × 1000 grams = 20.90909... × 1000 = 20909.09 grams

8 0
3 years ago
Read 2 more answers
In what year will the two quantities be​ equal?
Galina-37 [17]

Its the second because i did this already

3 0
4 years ago
From the set (76, 77, 78), use substitution to determine which value of x makes the equation true
jeyben [28]

Answer:

The answer is C.

Step-by-step explanation:

Multiply 4 by 76, 77, and 78.

4 * 76 = 304

4 * 77 = 308

4 * 78 = 312

304 = 304, so C is the correct answer.

Hope this helps!

7 0
3 years ago
If you had 1052 toothpicks and were asked to group them in powers of 6, how many groups of each power of 6 would you have? Put t
sukhopar [10]

1052 toothpicks can be grouped into 4 groups of third power of 6 (6^{3}), 5 groups of second power of 6 (6^{2}), 1 group of first power of 6 (6^{1}) and 2 groups of zeroth power of 6 (6^{0}).

The number 1052, written as a base 6 number is 4512

Given: 1052 toothpicks

To do: The objective is to group the toothpicks in powers of 6 and to write the number 1052 as a base 6 number

First we note that, 6^{0}=1,6^{1}=6,6^{2}=36,6^{3}=216,6^{4}=1296

This implies that 6^{4} exceeds 1052 and thus the highest power of 6 that the toothpicks can be grouped into is 3.

Now, 6^{3}=216 and 216\times 5=1080, 216\times 4=864. This implies that 216\times 5 exceeds 1052 and thus there can be at most 4 groups of 6^{3}.

Then,

1052-4\times6^{3}

1052-4\times216

1052-864

188

So, after grouping the toothpicks into 4 groups of third power of 6, there are 188 toothpicks remaining.

Now, 6^{2}=36 and 36\times 5=180, 36\times 6=216. This implies that 36\times 6 exceeds 188 and thus there can be at most 5 groups of 6^{2}.

Then,

188-5\times6^{2}

188-5\times36

188-180

8

So, after grouping the remaining toothpicks into 5 groups of second power of 6, there are 8 toothpicks remaining.

Now, 6^{1}=6 and 6\times 1=6, 6\times 2=12. This implies that 6\times 2 exceeds 8 and thus there can be at most 1 group of 6^{1}.

Then,

8-1\times6^{1}

8-1\times6

8-6

2

So, after grouping the remaining toothpicks into 1 group of first power of 6, there are 2 toothpicks remaining.

Now, 6^{0}=1 and 1\times 2=2. This implies that the remaining toothpicks can be exactly grouped into 2 groups of zeroth power of 6.

This concludes the grouping.

Thus, it was obtained that 1052 toothpicks can be grouped into 4 groups of third power of 6 (6^{3}), 5 groups of second power of 6 (6^{2}), 1 group of first power of 6 (6^{1}) and 2 groups of zeroth power of 6 (6^{0}).

Then,

1052=4\times6^{3}+5\times6^{2}+1\times6^{1}+2\times6^{0}

So, the number 1052, written as a base 6 number is 4512.

Learn more about change of base of numbers here:

brainly.com/question/14291917

6 0
3 years ago
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