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nordsb [41]
3 years ago
10

PLEASE HELP AND I WILL GIVE U A CHOCOLATE​

Mathematics
2 answers:
emmasim [6.3K]3 years ago
4 0

Answer:

I think it is <em><u>c </u></em>I hope it helps have a good day

maks197457 [2]3 years ago
3 0

Answer:

B is the answer

Step-by-step explanation:

(√(1.5³ * 1.5⁷))/1.5²

√ 1.5 ^(3+7) ÷ 1.5²

√1.5^10 ÷ 1.5²

1.5⁵ ÷ 1.5²

1.5^(5-2)

1.5³

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PLEASE HELP I WILL MAKE BRAINLIST
kotykmax [81]

Answer:

22

Step-by-step explanation:

Generate the terms of sequence T using the nth term formula n² - 3

a₁ = 1² - 3 = 1 - 3 = - 2

a₂ = 2² - 3 = 4 - 3 = 1

a₃ = 3² - 3 = 9 - 3 = 6

a₄ = 4² - 3 = 16 - 3 = 13

a₅ = 5² - 3 = 25 - 3 = 22

22 is common to sequence S and T

6 0
3 years ago
Which of the following angles is in the solution set of sec^2θ - 3secθ - 2 = 0 for 0° ≤ θ &lt; 360°.
STALIN [3.7K]
1 / cos^2 O - 3 / cos O - 2 = 0
1 - 3 cos O -  2 cos^2 O = 0

2 cos^2 O + 3 cos O - 1 = 0

cos O = 0.2807 , -1.78   ( -1.78 cannot be a solution)

O = 74 degrees  (from  0.2807) another solution is 360-74 =  286 degrees

Its D
4 0
3 years ago
Kaylib’s eye-level height is 48 ft above sea level, and addison’s eye-level height is 85 and one-third ft above sea level. how m
GalinKa [24]

The addison see to the horizon at 2 root 2mi.

We have given that,Kaylib’s eye-level height is 48 ft above sea level, and addison’s eye-level height is 85 and one-third ft above sea level.

We have to find the how much farther can addison see to the horizon

<h3>Which equation we get from the given condition?</h3>

d=\sqrt{\frac{3h}{2} }

Where, we have

d- the distance they can see in thousands

h- their eye-level height in feet

For Kaylib

d=\sqrt{\frac{3\times 48}{2} }\\\\d=\sqrt{{3(24)} }\\\\\\d=\sqrt{72}\\\\d=\sqrt{36\times 2}\\\\\\d=6\sqrt{2}....(1)

For Addison h=85(1/3)

d=\sqrt{\frac{3\times 85\frac{1}{3} }{2} }\\d\sqrt{\frac{256}{2} } \\d=\sqrt{128} \\d=8\sqrt{2} .....(2)

Subtracting both distances we get

8\sqrt{2}-6\sqrt{2}  =2\sqrt{2}

Therefore, the addison see to the horizon at 2 root 2mi.

To learn more about the eye level visit:

brainly.com/question/1392973

5 0
3 years ago
Can someone please help me
Alex Ar [27]
We are trying to find the length of the side opposite to the 20 degree angle. We are given the hypotenuse, so we can use the trigonometric function sine to solve for x.

sin(theta) = opposite / hypotenuse

sin(20) = x/18

18sin(20) = x

x = 6.1564

The answer to the nearest tenth is 6.2





5 0
3 years ago
Explain how to estimate 585 - 321 two different ways
yKpoI14uk [10]
<span>Explain how to estimate 585 - 321 two different ways
just subtract them</span>
6 0
3 years ago
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