All categories

3 years ago

4 points

Mathematics

1 answer:

USPshnik [31]3 years ago

5 0

Answer:

C $1.75

Step-by-step explanation:

$469 divided by 268 is $1.75, so it's $1.75 per item

You might be interested in

Line segment TS is tangent to circle O at point N.

Natalka [10]

Answer:

the answer is 148

Step-by-step explanation:

5 0

2 years ago

Read 2 more answers

jasmine has 8 seashells. three- quarters are clamshells. how many shells are clamshells 3/4=_/8 a)3 shells b)4 shells c) 6 shell

fgiga [73]

The answer for your question is 6/8

6 0

3 years ago

If the Leaning Tower of Pisa (which is roughly cylindrical) has a height of 55 meters, radius of 8 meters, what is the volume?

valentinak56 [21]

Answer:

Option C. $V=3,520\pi\ m^3$

Step-by-step explanation:

we know that

The volume of a cylinder is equal to

$V=\pi r^{2} h$

we have

$r=8\ m$

$h=55/ m$

substitute

$V=\pi (8)^{2} (55)$

$V=3,520\pi\ m^3$

8 0

3 years ago

Read 2 more answers

Suppose that the mean water hardness of lakes in Kansas is 425 mg/L and these values tend to follow a normal distribution. A lim

tino4ka555 [31]

Answer:

The mean water hardness of lakes in Kansas is 425 mg/L or greater.

Step-by-step explanation:

We are given the following data set:

346, 496, 352, 378, 315, 420, 485, 446, 479, 422, 494, 289, 436, 516, 615, 491, 360, 385, 500, 558, 381, 303, 434, 562, 496

Formula:

$\text{Standard Deviation} = \sqrt{\displaystyle\frac{\sum (x_i -\bar{x})^2}{n-1}}$

where $x_i$ are data points, $\bar{x}$ is the mean and n is the number of observations.

$Mean = \displaystyle\frac{\text{Sum of all observations}}{\text{Total number of observation}}$

$Mean =\displaystyle\frac{10959}{25} =438.36$

Sum of squares of differences = 175413.76

$S.D = \sqrt{\dfrac{175413.76}{24}} = 85.49$

Population mean, μ = 425 mg/L

Sample mean, $\bar{x}$ = 438.36

Sample size, n = 25

Alpha, α = 0.05

Sample standard deviation, s = 85.49

First, we design the null and the alternate hypothesis

$H_{0}: \mu \geq 425\text{ mg per Litre}\\H_A: \mu < 425\text{ mg per Litre}$

We use one-tailed t test to perform this hypothesis.

Formula:

$t_{stat} = \displaystyle\frac{\bar{x} - \mu}{\frac{s}{\sqrt{n}} }$

Putting all the values, we have

$t_{stat} = \displaystyle\frac{438.36 - 425}{\frac{85.49}{\sqrt{25}} } = 0.7813$

Now, $t_{critical} \text{ at 0.05 level of significance, 24 degree of freedom } = -1.7108$

Since,

The calculated t-statistic is greater than the critical value, we fail to reject the null hypothesis and accept it.

Thus, the mean water hardness of lakes in Kansas is 425 mg/L or greater.

6 0

3 years ago

For the vulcan species, if the probability that a couple produces a girl is 0.202, and if the couple has 6 children, what is the

Andru [333]

2 boys 4 girls Add those together then divid And Then Use diffences And theres ur Awnser

6 0

3 years ago