It takes 4.3 seconds for the rocket to return to earth.
The equation is:

where -9.8m/sec² is the acceleration due to gravity, v₀ is the initial velocity, and h₀ is the initial height. We will go from the assumption that the rocket is launched from the ground, so h₀=0, and we are told that the initial velocity, v₀, is 42. This gives us:

We will use the quadratic formula to solve this. The quadratic formula is:

Plugging in our information we have:

x=0 is when the rocket is launched; x=4.3 is when the rocket lands.
Hi there
a/(a² - 36) + 2/(a-6) = 1/(a+6)
a/(a+6)(a-6) + 2/(a-6) = 1/(a+6)
Now we need to multiply the terms by (a+6)(a-6)
a + 2(a+6) = 1(a-6)
a + 2a + 12 = a - 6
3a + 12 = a - 6
3a - a = -6 - 12
2a = -18
Divide both sides by 2
2a/2 = -18/2
a = -9
Thus, The correct option is A
I hope that's help !
Good luck !
G(x) = 3x + 1, evaluate g(-2).
Simply plug in (- 3) in g(x)
g(-2) = 3(-2) + 1
g(-2) = - 6 +1
g(-2) = - 5
Answer:
I'm sorry I couldn't help you
Step-by-step explanation: