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hjlf
3 years ago
14

Please help me find an equation for this

Mathematics
1 answer:
satela [25.4K]3 years ago
4 0

Answer:

The equation that represents this situation is x + 3x + (x - 4) + 2(x - 4) = 72, where x is Erik's age

Step-by-step explanation:

Let us solve the question

Assume that Erik is x years old

∵ Erik is x years old

∵ Erik is \frac{1}{3} as old as Dawn

→ That means x = \frac{1}{3} Dawn

∴ x = \frac{1}{3} Dawn

→ Multiply both sides by 3

∴ 3x = Dawn

∴ Dawn is 3x years old

∵ Jiro is 4 years younger than Erik

→ That means Jiro = x - 4

∴ Jiro is (x - 4) years old

∵ Alita is 2 times as old as Jiro

→ That means Alita = 2 × (x - 4)

∴ Alita = 2 × (x - 4)

∴ Alita is 2(x - 4) years old

∵ The sum of all their ages is 72

→ That means add their ages and equate the sum by 72

∴ Erike's age + Dawn's age + Jiro's age + Alita's age = 72

∴ x + 3x + (x - 4) + 2(x - 4) = 72

The equation that represents this situation is x + 3x + (x - 4) + 2(x - 4) = 72, where x is Erik's age

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What would be the equation of the midline of this graph?
andrey2020 [161]

Answer:

Step-by-step explanation:

Vertices of the quadrilateral ABCD are,

A → (-5, 2)

B → (-3, 4)

C → (-2, 4)

D → (-1, 2)

By reflecting the given quadrilateral ABCD across x-axis to form the image quadrilateral A'B'C'D',

Rule for the reflection of a point across x-axis is,

(x, y) → (x , -y)

Coordinates of the image point A' will be,

A(-5, 2) → A'(-5, -2)

From the picture attached, point E is obtained by translation of point A'.

Rule for the translation of a point by h units right and k units up,

A'(x+h, y+k) → E(x', y')

By this rule,

A'(-5 + h, -2 + k) → E(1, -1)

By comparing coordinates of A' and E,

-5 + h = 1

h = 6

-2 + k = -1

k = 1

That means

Rule for the translation will be,

[(x + 6), (y + 1)]

5 0
3 years ago
Estion 4
Sunny_sXe [5.5K]

Answer:

Check Explanation

Step-by-step explanation:

Sale price = GHS80 per unit from first week of December to first week of January.

And at a reduced price of 30% from second week of January to the last week of January.

So, sales price for the second period = 70% × 80 = GHS56

To now find the profits for each of the purchase alternatives, we need to calculate the expected total demand

Expected demand units = (Demand × Probability)

First Period

Demand Probability | Expected demand units

500 0.1 | 50

600 0.3 | 180

750 0.4 | 300

850 0.2 | 170

Second period

Demand Probability | Expected demand units

320 0.5 | 160

180 0.3 | 54

130 0.2 | 26

Total expected demand units for first period = 50 + 180 + 300 + 170 = 700

Total expected demand units for second period = 160 + 54 + 26 = 240

i) When a pack of 600 products only is ordered, it is evident that it will cater for only the first period.

Expected Profit = (Expected sales it can cater for) - (Price of one pack of 600 products)

Expected sales it can cater for = 600 × 80 = GHS 48,000

Expected price of one pack of 600 products = 600 × 60 = GHS 36,000

Expected profit = 48000 - 36000 = GHS 12,000

ii) When a pack of 800 products only is ordered, it is evident that it will cater for the entire first period (700) and 100 from the second period.

Expected Profit = (Expected sales it can cater for) - (Price of one pack of 800 products)

Expected sales it can cater for = (700 × 80) + (100 × 56) = 56,000 + 5,600 = GHS 61,600

Expected price of one pack of 800 products = 800 × 57 = GHS 45,600

Expected profit = 61600 - 45600 = GHS 16,000

iii) When a pack of 1000 products only is ordered, it is evident that it will cater for the entire period, 700 and 240.

Expected Profit = (Expected sales it can cater for) - (Price of one pack of 1000 products)

Expected sales it can cater for = (700 × 80) + (240 × 56) = 56,000 + 13,440 = GHS 69,440

Expected price of one pack of 100 products = 1000 × 52 = GHS 52,000

Expected profit = 69440 - 52000 = GHS 17,440

iv) To do this, we first assume that

- the probabilities provided are very correct.

- the products are sold on a first come first serve basis

- the profits per unit for each period is calculated too.

Profit per product in this case = (16000/800) = GHS 20

For the first period

Expected profit = (700 × 80) - (700 × 57) = GHS 16,100

Average profit per unit = (16100/700) = GHS 23

For the second period

Expected profit = (100 × 56) - (100 × 57) = - GHS 100

Average profit per unit = (-100/100) = -GHS 1

Standard deviation = √[Σ(x - xbar)²/N]

Σ(x - xbar)² = [700 × (23-20)²] + [100 × (-1-20)²]

= 6300 + 44,100 = 50,400

N = 800

Standard deviation per unit = √(50400/800) = GHS 7.94

Variance per unit = (standard deviation per unit)² = (7.94)² = 63.

Variance on 800 units = 800 (1² × 63) = 800 × 63 = 50,400

Standard deviation on profits of 800 units = √(50400) = GHS 224.5

v) With the same assumptions as in (iv), but now, we include the Profit (or more appropriately, the loss from unsold units of products)

Profit per product in this case = (17440/1000) = GHS 17.44

For the first period

Expected profit = (700 × 80) - (700 × 52) = GHS 19,600

Average profit per unit = (19600/700) = GHS 28

For the second period

Expected profit = (240 × 56) - (240 × 52) = - GHS 960

Average profit per unit = (960/240) = GHS 4

The expected unsold products = 1000 - 940 = 60

Profit on those unsold products = 0 - (60 × 52) = -GHS 3,120

Profit per unit = (-3120/60) = - GHS 52

Standard deviation = √[Σ(x - xbar)²/N]

Σ(x - xbar)² = [700 × (28-17.44)²] + [240 × (4-17.44)²] + [60 × (-52-17.44)²]

= 78,059.52 + 43,352.064 + 289,314.816 = 410,726.4

N = 1000

Standard deviation per unit = √(410,726.4/1000) = GHS 20.27

Variance per unit = (standard deviation per unit)² = (20.27)² = 410.7264

Variance on 1000 units = 1000 (1² × 410.7264) = 800 × 410.7264 = 410,726.4

Standard deviation on profits of 1000 units = √(410,726.4) = GHS 640.88

vi) The standard deviation on profits show how much the real profits can range below or abobe the expected profit. That is, the standard deviation basically represents how big the risks or rewards can get.

A larger standard deviation will indicate a higher risk in case of loss and a higher reward in case of profits.

The option with the lower risk is the option with the lower standard deviation.

Hence, a pack of 800 products should be ordered instead of a pack of 1000 products as it has a lower standard deviation and hence, a lower risk attached to it thereby minimizing the risk.

Hope this Helps!!!

5 0
4 years ago
The length of a chalkboard is 5 feet.the width is 10 ft. mr Jones has 20 feet of string to place around it. Ms coley cuts off 3
11Alexandr11 [23.1K]
Mr jones does not have enough string to place around the chalkboard
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3 years ago
Read 2 more answers
Martha estimated the quotient of −71.81 and −8.02 using rounding to the nearest whole number. 9 StartLongDivisionSymbol 72 EndLo
Ilia_Sergeevich [38]

Answer:

(b) She should have rounded –8.02 to –8

Step-by-step explanation:

Given

See attachment for long division

Required

Her error

Ignoring the minus sign,

Her approximation is as follows:

-71.81 \approx 72

-8.02 \approx 9

Her approximation of -8.02 is wrong

Because:

-8.02 \approx 8

<em>Hence (b) is correct</em>

6 0
3 years ago
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270(pi/180)=3pi/2=theta
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