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pshichka [43]
3 years ago
7

The length of a chalkboard is 5 feet.the width is 10 ft. mr Jones has 20 feet of string to place around it. Ms coley cuts off 3

feet of the decoration, will there be enough string to place around the chalkboard?
Mathematics
2 answers:
adell [148]3 years ago
8 0

Answer:

nope he doesn't

Step-by-step explanation:

11Alexandr11 [23.1K]3 years ago
4 0
Mr jones does not have enough string to place around the chalkboard
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13 cm

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Find the distance from point A(−9,−3) to the line y = x−6. Round your answer to the nearest tenth.
Vladimir79 [104]

The distance from point A(−9,−3) to the line y = x−6 is 8.5 units

<u>What is slope ?</u>

A line's steepness is determined by its slope. In mathematics, slope is determined by "rise over run" (change in y divided by change in x).

step 1

Find the slope of the perpendicular line to the given line

y=x-6 ---> given line

The slope is m=1

Remember that

If two lines are perpendicular, then their slopes are opposite reciprocal (the product of their slopes is equal to -1)

m1*m2 = -1

we have

m1=1

substitute

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so

m2 = -1

step 2

Find the equation of the perpendicular line to the given line

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y-y1=m(x-x1)

we have

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(x1,y1)=(−9,−3)

substitute

y+3=-1(x+9)--> equation in point slope form

y+3= -x-9

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step 3

Find the intersection point between the given line and the perpendicular line to the given line

we have the system of equations

y = x−6.

y= -x-12

Solve the system by graphing

The intersection point is (-3,-9)

see the attached figure

step 4

we know that

The distance between the point A and the point (-3,-9) is the same that the distance between point A and the line y=x-6

the formula to calculate the distance between two points is equal to

d=√[(y2-y1)² + (x2-x1)²]

substitute the values

d=√[(-9+3)² + (-3+9)²]

d= √72 units

simplify

d= 6√2 = 8.5 units

To learn more about the slope from the given link

brainly.com/question/16949303

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Answer:

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Step-by-step explanation:

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