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3 years ago

It’s either C or D? Please help

Mathematics

1 answer:

satela [25.4K]3 years ago

8 0

Answer:

Step-by-step explanation:

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X^2 + 5x - 24 = 0 How do I solve by factoring

tiny-mole [99]

Answer:

x = -8 or x = 3

Step-by-step explanation:

To factor ax² + bx + c, use AC method.

a times c is 1 × -24 = -24.

Factors of ac (-24) that add up to b (5) are 8 and -3.

Divide by a and reduce: 8/1 and -3/1.

Therefore, the factors are x + 8 and x − 3.

x² + 5x − 24 = 0

(x + 8) (x − 3) = 0

x = -8 or 3

7 0

4 years ago

Divide the following complex numbers: (5-i)/(4+3i)

skelet666 [1.2K]

Answer:

$\frac{17}{25} -\frac{19}{25} i$

Step-by-step explanation:

$\frac{5-i}{4+3i}$

$= \frac{17}{25} -\frac{19}{25} i$

7 0

3 years ago

Solve for y<br> 4y + 8 = 29 - 5y

andriy [413]

Answer:

7/3

Step-by-step explanation

4y+8=29-5y

First you are going to subtract 8 from both sides of the equation.

4y=21-5y

Next you are going to add 5y to each side of the equation.

9y=21

Now write it as a fraction,

9/21

Last but not least simplify.

3/7

8 0

3 years ago

Read 2 more answers

Doug is making food for a family party. He makes 5 cheesesteak sandwiches using 6 pounds of steak and 16 turkey burgers using 4

dalvyx [7]

Answer:

4 pounds

Step-by-step explanation:

16 ÷ 4 = 4

3 0

3 years ago

At one company a level 1 engineer receives a salary of $45,000 and a level 2 receives a salary of $65,000. The company has a bud

kkurt [141]

Answer:

Company will hire 3 Engineers of Level 1 and 10 Engineers of level 2.

Step-by-step explanation:

Let the number of engineers for level 1 be x.

Let the number of engineers for level 2 be y.

Given:

Total Number of engineers company can hire = 13

Now Total number of engineers are equal to sum of number of engineers for level 1 and number of engineers for level 2.

Hence Framing in the equation form we get;

$x+y=13 \ \ \ \ equation\ 1$

Also Given:

Salary of level 1 engineers = $45,000

Salary of level 2 engineers = $65,000

Total Budget of Company = $785,000

But Total Budget of Company depends upon the sum of Salary of level 1 engineers multiplied with number of level 1 engineers and Salary of level 2 engineers multiplied with number of level 2 engineers.

Hence equation can be framed as;

$45000x+65000y = 785000$

Dividing by 5000 on both side we get;

$\frac{45000x}{5000}+\frac{65000y}{5000}=\frac{785000}{5000}\\\\9x+13y=157 \ \ \ \ equation\ 2$

Now Multiplying equation 1 by 9 we get;

$9(x+y)=13\times9\\9x+9y= 117 \ \ \ \ equation\ 3$

Now Subtracting equation 3 from equation 2 we get;

$(9x+13y)-(9x-9y)=157-117\\\\9x+13y-9x-9y=40\\\\4y=40\\\\y=\frac{40}{4} =10$

Now Substituting the value of y in equation 1 we get

$x+y=13\\x+10=13\\x=13-10\\x=3$

Hence Company will hire 3 Engineers of Level 1 and 10 Engineers of level 2.

5 0

4 years ago