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3 years ago

How much does it cost to buy 10 pizzas

Mathematics

2 answers:

NNADVOKAT [17]3 years ago

6 0

Estimate:

70 dollars ($70)

Zinaida [17]3 years ago

5 0

Answer:it would cost $50 to buy 10 pepperoni pizza from little cecers.

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Linda had 84 fliers to post around town. Last week, she posted 1/3 of them. This week, she posted 2/7 of the remaining fliers. H

Jobisdone [24]

The remaining number of flires that Linda still not posted is 40.

According to the given question.

The total number of fliers Linda have = 84

Fraction of fliers Linda posted = 1/3

And, fraction of fliers Linda posted second time from the remaning fliers = 2/7

Now,

1/3 of 84 fliers = 1/3 × 84 = 28

So, the number of fliers are left with Linda after first posting = 84 - 28 = 56

Again she posted 2/7 fliers. The number of flires Linda posted second time is given by

⇒ 2/7 × 56 = 16

Thereore, the number of fliers that Lindna still not posted = 56 - 16 = 40

Hence, Linda still not posted 40 fliers.

Find out more information about fraction and remaining numbers here:

brainly.com/question/2254581

#SPJ4

4 0

1 year ago

PLEASE HELP ME, FIRST ANSWER WILL GET BRAINLEST!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!

Bumek [7]

11. 2x+3x+1=21
5x+1 =21
5x=20
x=4
TU= 2(4) which is 8
UB= 3(4)+1 which is 13

12. 4x-1 +2x-1=5x
6x-2=5x
-2=-1x
2=x

X=2
TU= 7
UB= 3
TB=10

Problem 13:

2x-8=x+17
2x=x+25
x=25
AB =42
BC=42
AC=84

Problem 14:
3x-31
-x+6
=
2x-37 for BC part now we solve for x
x+6=2x-37
6=x-37
43=x
So :
X=43
AB=49
AC=98
BC=49

5 0

3 years ago

Tickets for the baseball games were $2.50 for general admission and 50 cents for kids. If there were six times as many general a

Makovka662 [10]

There was 3000 general admission tickets sold and 500 kid ticket sold.

How did I get this?

First, we need to see what information we have.
$2.50 = General admission tickets = (G)
$0.50 = kids tickets = (K)
There were 6x as many general admission tickets sold as kids. G = 6K

We need two equations:
G = 6K
$2.50G + $.50K = $7750
Since, G = 6K we can substitute that into the 2nd equation.

2.50(6K) + .50K = 7750
Distribute 2.50 into the parenthesis

15K + .50K = 7750
combine like terms

15.50K = 7750
Divide both sides by 15.50, the left side will cancel out.

K = 7750/15.50
K = 500 tickets
So, 500 kid tickets were sold.

Plug K into our first equation (G = 6k)

G = 6*500
G = 3000 tickets

So, 3000 general admission tickets were sold,

Let's check this:

$2.50(3000 tickets) = $7500 (cost of general admission tickets)
$.50(500 tickets) = $250 (cost of general admission tickets)
$7500 + $250 = $7750 (total cost of tickets)

4 0

3 years ago

In a normal distribution, most numbers in the data set fall within one standard deviation of the mean. True or False

UkoKoshka [18]

Answer:

True

Step-by-step explanation:

4 0

3 years ago

A 15 ft. telephone pole has a wire that extends from the top of the pole to the ground. The wire and the ground form a 42° angle

Lorico [155]

Answer:

Correct choice is A

Step-by-step explanation:

Consider right triangle ABC formed by the telephone pole (side AB) and ground (side BC). In this triangle AC is the length of the wire, BC is the distance from the base of the pole to the spot where the wire touches the ground and AB=15 ft, ∠ACB=42°.

Then

$\sin 42^{\circ}=\dfrac{AB}{AC}\Rightarrow AC=\dfrac{AB}{\sin 42^{\circ}}=\dfrac{15}{\sin 42^{\circ}}\approx 22.4\ ft.$
$\tan 42^{\circ}=\dfrac{AB}{BC}\Rightarrow BC=\dfrac{AB}{\tan 42^{\circ}}=\dfrac{15}{\sin 42^{\circ}}\approx 16.7\ ft.$

8 0

4 years ago