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3 years ago

How much does it cost to buy 10 pizzas

Mathematics

2 answers:

NNADVOKAT [17]3 years ago

6 0

Estimate:

70 dollars ($70)

Zinaida [17]3 years ago

5 0

Answer:it would cost $50 to buy 10 pepperoni pizza from little cecers.

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The gallons of gasoline used varies directly with the number of miles driven. If 15 gallons cost $30, what is the cost of 7.5 ga

inn [45]

U will have some left but idn sry but give me a like for trying :p

7 0

3 years ago

Harper’s parents put $75 into her school lunch money account. Each meal she gets from school costs her $3.25. The school sends H

BaLLatris [955]

19.75 divided by 3.25 = m
M= 6.07692307692

Hope this helps :D

3 0

3 years ago

Find the value of x. Round the length to the nearest 10th the diagram is not shown to scale

Ilia_Sergeevich [38]

In the given diagram:
measure angle DAB + measure angle BAC = 90 degrees
we are given that measure angle DAB = 10 degrees
Therefore:
measure angle BAC = 90 - 10 = 80 degrees

Now, triangle ABC is a right-angled triangle which means that we can use the trigonometric functions.
The function that we will use is:
cos theta = (adjacent) / (hypotenuse) where
theta = 80 degrees
adjacent = 500
hypotenuse is "x" that we want to calculate.

Substitute to get x as follows:
cos 80 = 500 / x
x = 500 / cos 80 = 500 / 0.1736 = 2879.4 m

6 0

3 years ago

How to do question 1?Had no idea how to do both parts

givi [52]

$y=\dfrac{\ln x}{3x-6}$

Differentiate both sides with respect to $x$ :

$\dfrac{\mathrm dy}{\mathrm dx}=\dfrac{\frac{3x-6}x-3\ln x}{(3x-6)^2}$

When $x=1$ , you have

$\dfrac{\mathrm dy}{\mathrm dx}=\dfrac{\frac{3-6}1-3\ln1}{(3-6)^2}=\dfrac{-3}9=-\dfrac13$

For part (b), we now assume that $x$ and $y$ are functions of an independent variable, which we'll call $t$ (for time). Now differentiating both sides with respect to $t$ , we have

$\dfrac{\mathrm dy}{\mathrm dt}=\dfrac{\frac{3x-6}x-3\ln x}{(3x-6)^2}\dfrac{\mathrm dx}{\mathrm dt}$

where the chain rule is used on the right side. We're told that $y$ is decreasing at a constant rate of 0.1 units/second, which translates to $\dfrac{\mathrm dy}{\mathrm dt}=-0.1$ . So when $x=1$ , you have

$-0.1=\dfrac{\frac{3-6}1-3\ln1}{(3-6)^2}\dfrac{\mathrm dx}{\mathrm dt}$
$-0.1=-\dfrac13\dfrac{\mathrm dx}{\mathrm dt}$
$\dfrac{\mathrm dx}{\mathrm dt}=0.3$

where the unit is again units/second.

6 0

3 years ago

PLEASE HELP!!

juin [17]

Answer:-1

Step-by-step explanation:I't is the most reasonable answer

(P.S. I just took the quiz and i got it right.So you guys should trust me.)

6 0

3 years ago