Well we would know if you told us the ingridients
Answer:
78 dollars
Step-by-step explanation:
Answer:
It isn't a vector space
Step-by-step explanation:
If f and g were elements of the set, then the sum f+g should be an element of the set. However the sum of quadratic funcitons may not neccesarily be a quadratic function. Lets look at
f(x) = x²+ x + 5
g(x) = -x²+5
Both f and g are quadratic functions and the graphs of both functions contain the point (0,5), because f(0) = g(0) = 5. However f(x) + g(x) = (x²+x+5)+(-x²+5) = x+10, which is not a quadratic funciton. Furthermore, f+g(0) = 10, so its graph doesnt contain the point (0,5). This shows that f+g is not in the set, therefore, the set cant be a vector space.
Do you want to find the rate of change?
Answer:
NC = 7.7
C = 63.6°
T = 26.4°
Step-by-step explanation:
✔️Apply pythagorean theorem to find the length of NC:
NC = √(17.2² - 15.4²) = √58.68
NC ≈ 7.7
✔️Apply trigonometric function to find Angle T:
Reference angle = T
Hypotenuse = 17.2
Adjacent length = 15.4
Apply CAH, thus:
![Cos(T) = \frac{Adj}{Hyp}](https://tex.z-dn.net/?f=%20Cos%28T%29%20%3D%20%5Cfrac%7BAdj%7D%7BHyp%7D%20)
![Cos(T) = \frac{15.4}{17.2}](https://tex.z-dn.net/?f=%20Cos%28T%29%20%3D%20%5Cfrac%7B15.4%7D%7B17.2%7D%20)
![T = cos^{-1}(\frac{15.4}{17.2})](https://tex.z-dn.net/?f=%20T%20%3D%20cos%5E%7B-1%7D%28%5Cfrac%7B15.4%7D%7B17.2%7D%29%20)
T ≈ 26.4°
✔️C = 180 - (90 + 26.4) (sum of triangle)
C = 63.6°