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BabaBlast [244]
3 years ago
11

Question 8 plz will give brainlest

Mathematics
1 answer:
Wittaler [7]3 years ago
6 0

Answer:

the answer for question no 8 is. option second...ie 17

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How to do this question plz answer ​
ANEK [815]

9514 1404 393

Answer:

  more than half are being used

Step-by-step explanation:

Perhaps easiest to understand is the most straightforward: figure the total number of seats and the number of seats being used. Check to see if that is more than half.

The 1 first-class carriage has usage of ...

  (3/8)(64 seats) = 24 seats.

The 6 standard carriages have usage of ...

  (7/13)(6 · 78 seats) = 252 seats.

The total number of seats used is ...

  24 + 252 = 276 . . . . seats used

__

The total number of seats on the train is ...

  1·64 +6·78 = 532 . . . . seats on the train

Half of the seats on the train will be ...

  532/2 = 266 seats . . . . half the seats

The 276 used seats are more than half of the total number. More than half the seats are being used.

_____

<em>Alternate solution</em>

Another way to look at this is to compare utilization to 1/2 in each carriage class.

  In first class 1/2 -3/8 = 1/8 of 64 seats = 8 seats fewer than 1/2 the seats are being used.

  In standard class, 7/13 -1/2 = 14/26 -13/26 = 1/26 of 78 seats = 3 seats more than 1/2 the seats are being used. There are 6 standard class carriages, so 6·3 = 18 more than half the seats in the standard-class carriages are being used.

This number is 10 more than the 8 under-utilized seats in first class, so <em>more than half the train seats are being used</em>.

8 0
3 years ago
Which equation has only 1 solution? A. c+2=c+2 B. c= -c+2 C. c+2=c-2 D. c-c=2 Please explain.
zhannawk [14.2K]

Answer:

B. c= -c+2

Step-by-step explanation:

A. ...................

  • c+2=c+2
  • c-c= 2-2
  • 0=0

It has infinitely many solutions as the equation is correct for any value of c.

B. ...................

  • c= -c+2
  • c+c= 2
  • 2c = 2
  • c = 2/2
  • c= 1

It has one solution only

C. ...................

  • c+2=c-2
  • c-c= -2 - 2
  • 0 = -4

It has no solution as this equation is incorrect

D. ...................

  • c-c=2
  • 0 = 2

It has no solution as this equation is incorrect

6 0
3 years ago
What are the solutions of the compound inequality 2d + 3 ≤ –11 or 3d – 9 &gt; 15?
jolli1 [7]

Answer:

A. d ≤ –7 or d > 8.

Step-by-step explanation:

Given  : 2d + 3 ≤ –11 or 3d – 9 > 15.

To find : What are the solutions of the compound inequality .

Solution : We have given 2d + 3 ≤ –11 or 3d – 9 > 15.

For  2d + 3 ≤ –11

On subtracting both sides by 3

2d  ≤ –11 - 3 .

2d  ≤ –14.

On dividing both sides by 2 .

d  ≤ –7.

For  3d – 9 > 15.

On adding both sides by 9.

3d > 15 + 9 .

3d > 24 .

On dividing both sides by 3 .

d > 8 .

So, A. d ≤ –7 or d > 8.

Therefore,  A. d ≤ –7 or d > 8.

7 0
3 years ago
Solve the simultaneous equations
Sergio039 [100]

Answer:

the answer is (x,y) = (\frac{2}{161} , \frac{240}{101})

Step-by-step explanation:

6 0
3 years ago
Give the properties for the equation -2x 2 - y + 10x - 7 = 0.
Sladkaya [172]

Given:

The quadratic equation is

-2x^2-y+10x-7=0

To find:

The vertex of the given quadratic equation.

Solution:

If a quadratic function is f(x)=ax^2+bx+c, then

Vertex=\left(\dfrac{-b}{2a},f(\dfrac{-b}{2a})\right)

We have,

-2x^2-y+10x-7=0

It can be written as

-2x^2+10x-7=y

y=-2x^2+10x-7           ...(i)

Here, a=-2,b=10,c=-7.

\dfrac{-b}{2a}=\dfrac{-10}{2(-2)}

\dfrac{-b}{2a}=\dfrac{-10}{-4}

\dfrac{-b}{2a}=\dfrac{5}{2}

Putting x=\dfrac{5}{2} in (i), we get

y=-2(\dfrac{5}{2})^2+10(\dfrac{5}{2})-7

y=-2(\dfrac{25}{4})+\dfrac{50}{2}-7

y=\dfrac{-50}{4}+25-7

y=\dfrac{-25}{2}+18

On further simplification, we get

y=\dfrac{-25+36}{2}

y=\dfrac{11}{2}

So, the vertex of the given quadratic equation is \left(\dfrac{5}{2},\dfrac{11}{2}\right).

Therefore, the correct option is A.

3 0
3 years ago
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