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evablogger [386]
3 years ago
8

Find the missing angle A in the triangle

Mathematics
1 answer:
Jobisdone [24]3 years ago
6 0

Answer:

f. none of the above

Step-by-step explanation:

90 + 63 = 153

180 - 153 = 27

∠A = 27°

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Simplify<br> -4/7+(-4/3)
jasenka [17]

Answer:

40/21

Step-by-step explanation:

-4/7+(-4/3)

common factor is 21

=21/7×-4-21/3×4

=3×-4-7×4 all divided by 21

=-12-28 all divided by 21

=40/21

4 0
3 years ago
J.J.Bean sells a wide variety of outdoor equipment and clothing. The company sells both through mail order and via the internet.
melamori03 [73]

Answer:

99% confidence interval for the true mean difference between the mean amount of mail-order purchases and the mean amount of internet purchases is [$(-31.82) , $12.02].

Step-by-step explanation:

We are given that a random sample of 16 sales receipts for mail-order sales results in a mean sale amount of $74.50 with a standard deviation of $17.25.

A random sample of 9 sales receipts for internet sales results in a mean sale amount of $84.40 with a standard deviation of $21.25.

The pivotal quantity that will be used for constructing 99% confidence interval for true mean difference is given by;

                      P.Q.  =  \frac{(\bar X_1-\bar X_2)-(\mu_1-\mu_2)}{s_p \times \sqrt{\frac{1}{n_1}+\frac{1}{n_2} } }  ~ t__n_1_+_n_2_-_2

where, \bar X_1 = sample mean for mail-order sales = $74.50

\bar X_2 = sample mean for internet sales = $84.40

s_1 = sample standard deviation for mail-order purchases = $17.25

s_2 = sample standard deviation for internet purchases = $21.25

n_1 = sample of sales receipts for mail-order purchases = 16

n_2 = sample of sales receipts for internet purchases = 9

Also,  s_p =\sqrt{\frac{(n_1-1)\times s_1^{2}+(n_2-1)\times s_2^{2} }{n_1+n_2-2} }  =  \sqrt{\frac{(16-1)\times 17.25^{2}+(9-1)\times 21.25^{2} }{16+9-2} } = 18.74

The true mean difference between the mean amount of mail-order purchases and the mean amount of internet purchases is represented by (\mu_1-\mu_2).

Now, 99% confidence interval for (\mu_1-\mu_2) is given by;

             = (\bar X_1-\bar X_2) \pm t_(_\frac{\alpha}{2}_)  \times s_p \times \sqrt{\frac{1}{n_1} +\frac{1}{n_2}}

Here, the critical value of t at 0.5% level of significance and 23 degrees of freedom is given as 2.807.

          = (74.50-84.40) \pm (2.807  \times 18.74 \times \sqrt{\frac{1}{16} +\frac{1}{9}})

          = [$-31.82 , $12.02]

Hence, 99% confidence interval for the true mean difference between the mean amount of mail-order purchases and the mean amount of internet purchases is [$(-31.82) , $12.02].

5 0
3 years ago
a student bought a juice pouch for $2.50 and 3 bags of chips. the total cost was $5.05 write and solve an equation to determine
Wittaler [7]

First, write it as an equation

2.50+3x=5.05

Next, subtract 2.50 from both sides

2.50-2.50+3x=5.05-2.50

3x=2.55

Divide 3 on both sides

3x/3=2.55/3

x=0.85

The cost of a bag of chips is 0.85

hope i helped :D

5 0
3 years ago
Read 2 more answers
Please help me how many times can 3 go into 77
faust18 [17]

Answer:

3 can go into 77  25 times.

3 0
3 years ago
Sumy is working in geometry class and is given figure ABCD in the coordinate plane to reflect. The coordinates of point D are (a
Makovka662 [10]

Answer:

(b, a)

Step-by-step explanation:

Example if D was (3, 2) and reflects across y = x, D' will be (2, 3)

8 0
3 years ago
Read 2 more answers
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