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3 years ago

Two dice are rolled. What is the probability

Mathematics

1 answer:

mixas84 [53]3 years ago

8 0

Answer:

1/6

Step-by-step explanation:

1/6 chance

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A = a is an example of which algebraic property? A] Commutative Property of Multiplication

Sergio039 [100]

<span>A = a is an example of reflexive algebraic property.so correct answer is B
reflexive property</span>

6 0

3 years ago

Which statement is true?

Allisa [31]

Answer:

C is the correct answer

Step-by-step explanation:

50.6 and 50.600 are mathematically the same thing. Adding zeros at the end of a decimal does not increase its amount in this case.

3 0

3 years ago

Read 2 more answers

What is the equation for the points (-9,7) and (-6,-3)

andriy [413]

In point slope form, the equation is y-7=(-10/3)(x+9). In slope-intercept form, it is y=(-10/3)x-23.

First find the slope of the line. The formula for slope is

m=(y₂-y₁)/(x₂-x₁)

Using our points, we have

m=(-3-7)/(-6--9) = -10/3

Plug this into point slope form:

y-y₁=m(x-x₁)

y-7=(-10/3)(x--9)

y-7=(-10/3)(x+9)

Using the distributive property:

y-7=(-10/3)*x+(-10/3)*9

y-7=(-10/3)x-90/3

y-7=(-10/3)x-30

Add 7 to both sides:

y=(-10/3)x-23

4 0

3 years ago

In a large school, it was found that 77% of students are taking a math class, 74% of student are taking an English class, and 70

Iteru [2.4K]

Answer:

0.81 = 81% probability that a randomly selected student is taking a math class or an English class.

0.19 = 19% probability that a randomly selected student is taking neither a math class nor an English class

Step-by-step explanation:

We solve this question working with the probabilities as Venn sets.

I am going to say that:

Event A: Taking a math class.

Event B: Taking an English class.

77% of students are taking a math class

This means that $P(A) = 0.77$

74% of student are taking an English class

This means that $P(B) = 0.74$

70% of students are taking both

This means that $P(A \cap B) = 0.7$

Find the probability that a randomly selected student is taking a math class or an English class.

This is $P(A \cup B)$ , which is given by:

$P(A \cup B) = P(A) + P(B) - P(A \cap B)$

$P(A \cup B) = 0.77 + 0.74 - 0.7 = 0.81$

0.81 = 81% probability that a randomly selected student is taking a math class or an English class.

Find the probability that a randomly selected student is taking neither a math class nor an English class.

This is

$1 - P(A \cup B) = 1 - 0.81 = 0.19$

0.19 = 19% probability that a randomly selected student is taking neither a math class nor an English class

6 0

3 years ago

A pair of jeans is on sale for 25% off the original price. Which expression represents the sale

scZoUnD [109]

Answer:

$30

Step-by-step explanation:

If it's 25% off, then to find the sale price we just need to subtract 25% of the original price from the original price.

Original price is 40 so we do 40 - (40 * 0.25) = 30

6 0

3 years ago