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Serggg [28]
3 years ago
13

Can anyone tell me the correct answer of this. I already have it but I wanna make sure. please ​

Mathematics
1 answer:
Mamont248 [21]3 years ago
4 0

Answer:

x = 44.3°

Step-by-step explanation:

Redrawing the triangle,

To obtain x, we can apply the trigonometric relation :

Sin x = opposite / hypotenus

Opposite side = 6.5

Hypotenus = 9.3

Sin x = 6.5/9.3

x = sin^-1(6.5 / 9.3)

x = 44.34

x = 44.3°

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Solve for [x]. The pair of polygons are similar. The scale factor from A to B is 9:10​
brilliants [131]

Answer:

9

Step-by-step explanation:

if scale factor is 3/5, then

(x+12):35=3:5, ⇒

6 0
3 years ago
Help please. I'll give brainliest and 5 stars
kicyunya [14]

Answer:

AB=CB

Step-by-step explanation:

These have congruent side markings.

7 0
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You are playing a board game with your little sister. Moves are determined by rolling 2 six-sided dice. The red die tells you th
enot [183]

Answer: The probability is 1/9.

Step-by-step explanation:

First, let's define the possible outcomes of each dice:

Red: Forward (4 times), Backward (2 times)

Green : {1, 1, 2, 2, 3, 4}

We want to find the probability of moving backward 2 spaces.

Then we need to find the probability of rolling a "backward" in the red dice, and a 2 in the green dice.

First, the probability of rolling a backward in the red dice is equal to the quotient between the number of outcomes that are "backward", and the total number of outcomes in the dice (there are 2 backwards and 6 outcomes in total), this is:

p1 = 2/6 = 1/3.

And the probability of rolling a 2 in the green dice is equal to the quotient between the number of outcomes with a 2, and the total number of outcomes. (The 2 appears two times, and there are 6 possible outcomes):

p2 = 2/6 = 1/3.

Now, the probability of both events happening at the same time is equal to the product of the individual probabilities, then the probability of moving backwards 2 spaces is:

P = p1*p2 = (1/3)*(1/3) = 1/9.

7 0
3 years ago
The cost of 4 cookies, 6 doughnuts, and 3 boxes of doughnut holes is $8.15. The cost of 2 cookies, 3 doughnuts, and 4 boxes of d
Naddika [18.5K]

Answer:

$1.25

Step-by-step explanation:

This can best be determined using a set of linear equations that are solved simultaneously.

This pair of linear equations may be solved simultaneously by using the elimination method. This will involve ensuring that the coefficient of one of the unknown variables is the same in both equations.

Let the cost of a cookie be c, cost of a doughnut be d and that of a box of doughnut hole be h then if cost of 4 cookies, 6 doughnuts, and 3 boxes of doughnut holes is $8.15, we have

4a + 6d + 3h = 8.15

and the cost of 2 cookies, 3 doughnuts, and 4 boxes of doughnuts holes is $7.20 then

2a + 3d + 4h = 7.20

Dividing the first by 2

2a + 3d + 1.5h = 4.075

subtracting from the second equation

2.5h = 3.125

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5 0
3 years ago
Let p, q, and r represent the following statements"
Nitella [24]

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For this purpose there are, among others, the following logical operators: conjunction (and) ∧, disjunction (or) ∨, denial (not) ¬,  conditional (if - then) ⇒ and double conditional (if and only if, iff) ⇔.

So for this case we have:

Answer

a) Sam had pizza last night if and only if Chris finished her homework.

p⇔q

b) Pat watched the news this morning iff Sam did not have pizza last night.

r⇔¬p

c) Pat watched the news this morning if and only if Chris finished her homework and Sam did not have pizza last night.

r⇔(q∧¬p)

d) In order for Pat to watch the news this morning, it is necessary and sufficient that Sam had pizza last night and Chris finished her homework.

r⇔(p∧q)

e) <em>q ⇔ r</em>

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f) <em>p ⇔ (q ∧ r)</em>

Sam had pizza last night if and only if Chris finished his homework and Pat watched the news this morning

g) <em>(¬p) ⇔ (q ∨ r) </em>

Sam didn't have pizza last night if and only if Chris finished his homework or Pat watched the news this morning

h) <em>r ⇔ (p ∨ q) </em>

Pat watched the news this morning if Sam had pizza last night or Chris finished his homework

4 0
3 years ago
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