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jolli1 [7]
3 years ago
6

Which of the following is the total number of cubic units needed to fill a space figure​

Mathematics
1 answer:
attashe74 [19]3 years ago
8 0

Answer:

Volume is the required answer.

Step-by-step explanation:

The number of cubic units needed to fill the space inside a three-dimensional figure.

For example:- air in room, fluids in container, water in a bottle, etc.

I got this answer with complete explanation from Gauthmath app. They have the tutors who can answer our questions. In my opinion it's a very good app to get help. You don't even need to wait. I think you should check it out once.

<em>Hope </em><em>my </em><em>answer </em><em>helps.</em><em> </em><em>Best </em><em>of </em><em>luck!</em><em> </em><em />

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Need help ASAP <br> questions in the pics i have sent
Cloud [144]

Answer:

Step-by-step explanation:

Picture 1

In right triangle ABC,

Side AB is the opposite side of angle C.

Picture 2

In triangle MKL,

tan(∠M) = \frac{\text{Opposite side}}{\text{Adjacent side}}

             = \frac{KL}{KM}

             = \frac{15}{8}

Option (1) is the answer.

Picture 3

In ΔXYZ,

sin(∠Z) = \frac{\text{Opposite side}}{\text{Hypotenuse}}

            = \frac{XY}{XZ}

For the length of XY we will apply Pythagoras theorem in ΔXYZ,

XZ² = XY² + YZ²

XY² = XZ² - YZ²

      = (40)² - (32)²

XY = √576

     = 24

sin(Z) = \frac{24}{40}

sin(Z) = \frac{3}{5}

Picture 4

In right triangle DEF,

Cos(D) = \frac{\text{Adjacent side}}{\text{Hypotenuse}}

           = \frac{EF}{DF}

           = \frac{75}{72}

           = \frac{25}{24}

Picture 5

In ΔABC,

tan(63°) = \frac{\text{Opposite side}}{\text{Adjacent side}}

tan(63°) = \frac{BC}{AB}

AB = \frac{BC}{\text{tan}(63)}

AB = \frac{8}{\text{tan}(63)}

AB = 4.0762 ≈ 4 m

Option (3) will be the answer.

7 0
3 years ago
What is the solution of the equation 6x - 4 = 2(3x - 2). Explain your steps.​
Vikki [24]

Answer:<em><u> x= 4/3 but in decimal form =1.333</u></em>

Step-by-step explanation: Rearrange the equation by subtracting what is to the right of the equal sign from both sides of the equation :

                    4-(2*(3*x-2))=0

4 -  2 • (3x - 2)  = 0

Pull out like factors :

  8 - 6x  =   -2 • (3x - 4)  

Solve  :    3x-4 = 0  

Add  4  to both sides of the equation :  

                     3x = 4

Divide both sides of the equation by 3:

                    <em><u>x = 4/3 = 1.333</u></em>

7 0
3 years ago
Read 2 more answers
In one area, monthly incomes of technology-related workers have a standard deviation of $650. It is believed that the standard d
Virty [35]

Answer:

There is sufficient statistical evidence to prove that the standard deviation of the technology-related workers and the standard deviation of the non-technology workers are equal.

Step-by-step explanation:

Here we have our null hypothesis as H₀: σ² = s²

Our alternative hypothesis is then Hₐ: σ² ≠ s²

We therefore have a two tailed test

To test the hypothesis of difference in standard deviation which is the Chi squared test given as follows

\chi ^{2} = \dfrac{\left (n-1  \right )s^{2}}{\sigma ^{2}}

Where:

n = Size of sample

s² = Variance of sample = 950²

σ² = Variance of population = 650²

Degrees of freedom = n - 1 = 71 - 1 = 70

α = Significance level = 0.1

Therefore, we use 1 - 0.1 = 0.9

From the Chi-square table, we have the critical value as

1 - α/2 = 51.739,  

α/2 = 90.531

Plugging the values in the above Chi squared test equation, we have;

\chi ^{2} = \dfrac{\left (23-1  \right )950^{2}}{650 ^{2}} = 49.994

Therefore, since the test value within the critical region, we do not reject the null hypothesis, hence there is sufficient statistical evidence to prove that the standard deviation of the technology-related workers and the standard deviation of the non-technology workers are equal.

6 0
3 years ago
Triangle JKL and Triangle MNO are similar triangles.
STALIN [3.7K]
We need to work out first the scale factor of the side length

Side MN correspond to the side JK

Side MN = 3.5 cm
Side JK = 14 cm

Scale factor = 14/3.5 = 4

Side OM correspond to side LJ
Side OM = 12 cm
Side LJ = 12 × 4 = 48 cm
4 0
3 years ago
25. a 2018 pew research center survey found that more americans believe they could give up their televisions than could give up
geniusboy [140]

(a)Probability that a person could give up cell phone = 0.48

(b)Probability that a person who could give up her cell phone also could give up television is 0.65

(c) Probability that a person who could not give up a cell phone could give up television is 0.73

What is Probability?

Calculating the likelihood of experiments happening is one of the branches of mathematics known as probability. We can determine everything from the likelihood of receiving heads or tails when tossing a coin to the likelihood of making a research blunder, for instance, using a probability. It is crucial to grasp this branch's most fundamental concepts in order to fully comprehend it, including the formula for computing probabilities in equiprobable sample spaces, the likelihood of two events joining together, the probability of the complementary event, etc.

According to  the given question:

a. Probability that a person could give up cell phone = 0.48

b. Probability that a person who could give up her cell phone also could give up television

= P(give up cell phone and TV)/p(give up cell phone)

= 0.31/0.48

= 0.6458

= 0.65

c. Probability that a person who could not give up a cell phone could give up television is

= P(could not give up cellphone and could give up TV)/P(could not give up cell phone)

= 0.38/0.52

= 0.73

d. The probability a person could give up television is higher for persons who couldn't give up cell phones than for those who could give up their cell phones.

Hence,

(a)Probability that a person could give up cell phone = 0.48

(b)Probability that a person who could give up her cell phone also could give up television is 0.65

(c) Probability that a person who could not give up a cell phone could give up television is 0.73

To learn more about Probability, visit:

brainly.com/question/13604758

#SPJ4

5 0
1 year ago
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