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4 years ago

Fine the measure of z. A.70 B.80 C.83 D.87

Mathematics

2 answers:

shutvik [7]4 years ago

4 0

Answer:

Step-by-step explanation:

ArbitrLikvidat [17]4 years ago

4 0

Answer:A-70

Step-by-step explanation:

180-110=70

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Misha found that the equation -|2x-10|-1=2 had two possible solution x=3.5and x =-6.5. Which explains whether or not her solutio

Vika [28.1K]

<span>-|2x-10|-1=2 has NO solutions, because the absolute value function is never negative. Can be 0, can be positive, but can NOT be negative.

</span>

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4 years ago

Read 2 more answers

If b = 10 then a = 5<br><br> what id 2b+5a

MrRa [10]

2(10) +5(5)= 45

b=10 a=5

Plug in the values b and a.

7 0

2 years ago

Please could you find the answers to the questions in the attachment.

Fudgin [204]

( $\frac{x1+x2}{2} , \frac{y1+y2}{2}$ )we need 3 equations
1. midpoint equation which is ( $\frac{x1+x2}{2} , \frac{y1+y2}{2}$ ) when you have 2 points

2. distance formula which is D= $\sqrt{(x2-x1)^{2}+(y2-y1)^{2}}$

3. area of trapezoid formula whhic is (b1+b2) times 1/2 times height

so

x is midpoint of B and C
B=11,10
c=19,6
x1=11
y1=10
x2=19
y2=6
midpoint=( $\frac{11+19}{2} , \frac{10+6}{2}$ )
midpoint=( $\frac{30}{2} , \frac{16}{2}$ )
midpoint= (15,8)

point x=(15,8)

y is midpoint of A and D
A=5,8
D=21,0
x1=5
y1=8
x2=21
y2=0
midpoint=( $\frac{5+21}{2} , \frac{8+0}{2}$ )
midpoint=( $\frac{26}{2} , \frac{8}{2}$ )
midpoint=(13,4)

Y=(13,4)

legnths of BC and XY
B=(11,10)
C=(19,6)
x1=11
y1=10
x2=19
y2=6
D= $\sqrt{(19-11)^{2}+(6-10)^{2}}$
D= $\sqrt{(8)^{2}+(-4)^{2}}$
D= $\sqrt{64+16}$
D= $\sqrt{80}$
D= $4 \sqrt{5}$
BC= $4 \sqrt{5}$

X=15,8
Y=(13,4)
x1=15
y1=8
x2=13
y2=4
D= $\sqrt{(13-15)^{2}+(4-8)^{2}}$
D= $\sqrt{(-2)^{2}+(-4)^{2}}$
D= $\sqrt{4+16}$
D= $\sqrt{20}$
D= $2 \sqrt{5}$
XY= $2 \sqrt{5}$

the thingummy is a trapezoid
we need to find AD and BC and XY
we already know that BC= $4 \sqrt{5}$ and XY= $2 \sqrt{5}$

AD distance
A=5,8
D=21,0
x1=5
y1=8
x2=21
y2=0
D= $\sqrt{(21-5)^{2}+(0-8)^{2}}$
D= $\sqrt{(16)^{2}+(-8)^{2}}$
D= $\sqrt{256+64}$
D= $\sqrt{320}$
D= $4 \sqrt{2}$
AD= $4 \sqrt{2}$

so we have
AD= $4 \sqrt{2}$
BC= $4 \sqrt{5}$
XY= $2 \sqrt{5}$

AD and BC are base1 and base 2
XY=height
so
(b1+b2) times 1/2 times height
( $4 \sqrt{2}+4 \sqrt{5}$ ) times 1/2 times $2 \sqrt{5}$ =
( $4 \sqrt{2}+4 \sqrt{5}$ ) times \sqrt{5} [/tex] =
$4 \sqrt{10}+4*5$ = $4 \sqrt{10}+20$ =80 $\sqrt{10}$ =252.982

X=(15,8)
Y=(13,4)
BC= $4 \sqrt{5}$
XY= $2 \sqrt{5}$
Area=80 $\sqrt{10}$ square unit or 252.982 square units

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3 years ago

In the diagram below, AB, BC and CD are three sides of a regular polygon.

Y_Kistochka [10]

Answer:

BR is about 7.3084 cm

Step-by-step explanation:

the sum of the exterior angles of any polygon is 360. The measure ox x would be 360/15= 24

since I want BR, I will use cos (adj/hyp)

cos24=s/8

.9135=s/8

7.3084=s

3 0

3 years ago

Over the summer, for every 11 okra seeds Dana planted, 6 grew into plants. If he planted 110 okra seeds, how many grew into plan

PilotLPTM [1.2K]

Answer:

Step-by-step explanation:

write it as a ratio

11:6 = 110: x

cross multiply

11x= 660

divide by 11 on both sides

x= 60

5 0

3 years ago