Ask question

Ask question

All categories

Alex_Xolod [135]

3 years ago

8

Please help me on this problem

1 answer:

chubhunter [2.5K]3 years ago

3 0

I believe this should be it.

You might be interested in

The Bobcats football coach logged the following yardage gains and losses over four plays of a game.

lions [1.4K]

Answer:
9.8x - 11.1x
Explanation:
25 - 5.2 = 9.8x
0.9 - 12 = -11,1y

Notice: I’m not sure but if it wrong, you could replaced with 10x - 11y which be better answer

5 0

2 years ago

Help ;-; me please;-;

Diano4ka-milaya [45]

Answer: 13 is c im pretty sure and 14 is a im think hope fully it helps

Step-by-step explanation:

8 0

2 years ago

Find out the answers to this

meriva

Answer:

$\tan \theta = - \frac{1}{5} = - 0.2$

$\cos \theta = 0.98$

$\sin \theta = - 0.196$

Step-by-step explanation:

It is given that $\cot \theta = - 5$ and $\theta$ is in the fourth quadrant.

So, only $\cos \theta$ will have positive value and $\sin \theta$ , $\tan \theta$ will have negative value.

Now, $\cot \theta = - 5$

⇒ $\tan \theta = \frac{1}{\cot \theta} = -\frac{1}{5}$ (Answer)

We know, that $\sec^{2} \theta - \tan^{2} \theta = 1$

⇒ $\sec \theta = \sqrt{1 + \tan^{2} \theta } = \sqrt{1 + (- \frac{1}{5} )^{2} } = 1.019$

{Since, $\cos \theta$ is positive then $\sec \theta$ will also be positive}

⇒ $\cos \theta = \frac{1}{\sec \theta} = \frac{1}{1.0198} = 0.98$ (Answer)

We know, that $\csc^{2} \theta - \cot^{2} \theta = 1$

⇒ $\csc \theta = - \sqrt{1 + \cot^{2} \theta } = - \sqrt{1 + (- 5 )^{2} } = - 5.099$

{Since, $\sin \theta$ is negative then $\csc \theta$ will also be negative}

⇒ $\sin \theta = \frac{1}{\csc \theta} = \frac{1}{- 5.099} = - 0.196$ (Answer)

4 0

3 years ago

How many Japanese yen are equal to $100?

disa [49]

If you mean american dollars (which you most likely do) then it would be:
100 = 12285.
1000 = 122850.
10.000 = 1228.10
hope i helped

3 0

2 years ago

Read 2 more answers

Give away 100 B points

SashulF [63]

Answer:

henlo -u-

Step-by-step explanation:

8 0

2 years ago

Read 2 more answers