f(x)=2x^2+0x-5
Find the vertex
0/4=0=x
Input x into the equation to find y or f(x)
0+0-5=f(x)
(0,-5) = Vertex
Now find a random x coordinate to input into the equation.
Let's do 4.
32+0-5=f(x)=27
It may not look like a parabola due to it being uneven.
Answer:
second one
Step-by-step explanation:
Because when you try to remove the brackets then you should multiply coefficient of x and coefficient of y by 2
So it will be 2x+18y
2*9=18
The distance between two points is given by:
d² = (x₂-x₁)² + (y₂ - y₁)²
9 = (x₂ - 4)² + (y₂ - 2)²
Now, we can check different ordered pairs in this equation to see which satisfies it:
The one that satisfies this equation is (4 , -1).
1= 12.2
8=97.6
and for the last one the answer is 10 :))
Answer:
256
Step-by-step explanation:
any number to the 0 power equals 1, so r^0 equals 1
then, you have (4(1))^4
4×1=4
4^4=256
