All categories

3 years ago

Which expression is equivalent to 2w?

Mathematics

1 answer:

zhannawk [14.2K]3 years ago

8 0

Answer:

The first one.

Step-by-step explanation:

w + w is having 2 w's, which is obviously 2w.

2w + w would be equal to 3w.

2w - w would be equal to w.

w + 2 is just w + 2.

You might be interested in

(5/2)x=5 please help me

alekssr [168]

Answer:

x=2.5

Step-by-step explanation:

2.5x=5

subtract 2.5 from itself and 5

x=2.5

4 0

3 years ago

The length of a rectangle is 3.5 inches more tan its width. The perimeter of the rectangle is 31 inches. Find the length and the

leonid [27]

Length (L): w + 3.5

width (w): w

Perimeter (P) = 2L + 2w

31 = 2(w + 3.5) + 2(w)

31 = 2w + 7 + 2w

31 = 4w + 7

24 = 4w

6 = w

Length (L): w + 3.5 = (6) + 3.5 = 9.5

Answer: width = 6 inches, length = 9.5 inches

8 0

3 years ago

I need help and please have the work with the ones that are harder

Elina [12.6K]

1. 6
2. -12
3. 0.75
4. 1.4
5.
6.
7.
8.
9. -0.7

6 0

3 years ago

What's the greatest number of pill bugs found

Nimfa-mama [501]

Yea do you have anything that can show for the question then I might help with your questions:)

6 0

4 years ago

Write the point-slope form of an equation of the line through the points (-4, 7) and (5, 3).

cupoosta [38]

Answer:

$y-7=-\frac{\displaystyle 4}{\displaystyle 9}(x+4)$

$y-3=-\frac{\displaystyle 4}{\displaystyle 9}(x-5)$

Step-by-step explanation:

Hi there!

Point-slope form: $y-y_1=m(x-x_1)$ where $m$ is the slope and $(x_1,y_1)$ is a point that falls on the line

1) Determine the slope (m)

$m=\frac{\displaystyle y_2-y_1}{\displaystyle x_2-x_1}$ where two given points are $(x_1,y_1)$ and $(x_2,y_2)$

Plug in the given points (-4, 7) and (5, 3):

$m=\frac{\displaystyle 3-7}{\displaystyle 5-(-4)}\\\\m=\frac{\displaystyle 3-7}{\displaystyle 5+4}\\\\m=\frac{\displaystyle -4}{\displaystyle 9}$

Therefore, the slope of the line is $-\frac{\displaystyle 4}{\displaystyle 9}$ . Plug this into $y-y_1=m(x-x_1)$ as $m$ :

$y-y_1=-\frac{\displaystyle 4}{\displaystyle 9}(x-x_1)$

2) Plug a point into $y-y_1=-\frac{\displaystyle 4}{\displaystyle 9}(x-x_1)$

$y-y_1=-\frac{\displaystyle 4}{\displaystyle 9}(x-x_1)$

Because we're given two points, there are two ways we can write this equation:

$y-y_1=-\frac{\displaystyle 4}{\displaystyle 9}(x-x_1)\\\\y-7=-\frac{\displaystyle 4}{\displaystyle 9}(x-(-4))\\\\y-7=-\frac{\displaystyle 4}{\displaystyle 9}(x+4)$

$y-3=-\frac{\displaystyle 4}{\displaystyle 9}(x-5)$

I hope this helps!

4 0

3 years ago