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erastova [34]
3 years ago
13

(c³d)a(cd⁷)aSimplify ​

Mathematics
1 answer:
Veseljchak [2.6K]3 years ago
5 0

Answer:

= c^4 d^8 a^2

Step-by-step explanation:

Apply exponent rule: aa= a^2

= c^3 da^2 cd^7

= c^4 da^2 d^7

= c^4 d^8 a^2

You might be interested in
1 1/5 · x/3 = 9/10<br> solve for x
riadik2000 [5.3K]

The value of x in the equation 1 1/5 - x/3 = 9/10 is 9/10

<h3>Fraction</h3>

1 1/5 - x/3 = 9/10

- x/3 = 9/10 - 1 1/5

- x/3 = 9/10 - 6/5

-x/3 = 9-12 / 10

-x/3 = -3/10

  • divide both sides by - 1/3

x = -3/10 ÷ - 1/3

= -3/10 × -3/1

x = 9/10

Learn more about fraction:

brainly.com/question/11562149

#SPJ1

5 0
2 years ago
Please help I will really appreciate it it's about systems of equation
ioda
The answer is the letter c and d
3 0
3 years ago
For decent amount of points! Hey can someone tell me the awnser?
igor_vitrenko [27]
I highly believe that the answer is 35
4 0
3 years ago
Simplify. Consider all cases. |14−(x−6)|
yanalaym [24]

Answer:

20-x; -20+x; -20-x; 20+x

Step-by-step explanation:

|14-x+6|

|20-x|

20-x; -20+x; -20-x; 20+x

4 0
3 years ago
Read 2 more answers
HELP PLEASE!! I DONT UNDERSTAND!!!!!!!!!! THANKS SO MUCH
8090 [49]

Hello, please consider the following.

We will multiply the numerator and denominator by

4+\sqrt{6x}

to get rid of the root in the denominator.

First of all, we cannot divide by 0, right? So, we need to make sure that the denominator is different from 0.

4-\sqrt{6x} =0\sqrt{6x}=4\\\\\text{Take the square}\\\\6x=4^2=16\\\\x=\dfrac{16}{6}=\dfrac{8}{3}

We need to take any x real number different from 8/3 then and simplify the expression.

Let's do it!

\begin{aligned}\dfrac{4}{4-\sqrt{6x}}&=\dfrac{4(4+\sqrt{6x})}{(4+\sqrt{6x})(4-\sqrt{6x})}\\\\&=\dfrac{4(4+\sqrt{6x})}{(4^2-\sqrt{6x}^2)}\\\\&=\dfrac{4(4+\sqrt{6x})}{(16-6x)}\\\\&=\dfrac{2(4+\sqrt{6x})}{(8-3x)}\\\\&\large \boxed{=\dfrac{8+2\sqrt{6x}}{8-3x}}\end{aligned}

Thank you

8 0
3 years ago
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