The radius of the circle tangent to sides AC and BC and to the circumcircle of triangle ABC.
r= 24.
<h3>What is the radius of the circle tangent to sides AC and BC and to the circumcircle of triangle ABC.?</h3>
Generally, the equation for side lengths AB is mathematically given as
Triangle ABC has side lengths
Where
- AB = 65,
- BC = 33,
- AC = 56.
Hence
r √ 2 · (89 √ 2/2 − r √ 2) = r(89 − 2r),
r = 89 − 65
r= 24.
In conclusion, The radius of the circle tangent to sides AC and BC and to the circumcircle of triangle ABC.
r= 24.
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Answer:
Surface area=114 cm^2
Step-by-step explanation:
Surface area of a cuboid is given be 2(lb+bh+lh). ATQ, l=3, h=3, b=8. Plugging them into the formula, we will get surface area=114 cm^2
Answer: The answer to 2c+15cd+9d+12=12.
Both lines are parallel, since they have the same slope of 2.
