3 years ago

Can you solve this????? Super hard!

Mathematics

2 answers:

pav-90 [236]3 years ago

5 0

The answer is J. 1/(x^2-x)

ivann1987 [24]3 years ago

4 0

Answer:

Step-by-step explanation:

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3 years ago

The set of points (1, 1), (2, 2), (3, 3) is collinear.

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3 years ago

Given: the function defined by f(x)=3x^2-4 Which statement is true? 1. f(0) = 0 2. f(-2) = f(2) 3. f(5)+ f(2) = f(7) 4. f(5) x f

sergeinik [125]

$f(x)=3x^2-4 \\ \Downarrow \\ f(0)=3 \times 0^2-4=0-4=-4 \\ -4 \not= 0 \\ f(0) \not= 0 \\
\hbox{statement 1 is false} \\ \\
f(-2)=3 \times (-2)^2-4 =3 \times 4-4=12-4=8 \\
f(2)=3 \times 2^2-4=3 \times 4-4=12-4=8 \\ 8=8
\\ f(-2)=f(2) \\
\hbox{statement 2 is true}$

$f(5)=3 \times 5^2-4=3 \times 25-4=75-4=71 \\ f(2)=8 \\
f(7)=3 \times 7^2-4=3 \times 49-4=147-4=143 \\
71+8 \not= 143 \\
f(5)+f(2) \not= f(7) \\ \hbox{statement 3 is false} \\ \\
f(5)=71 \\ f(2)=8 \\ f(10)=3 \times 10^2-4=3 \times 100-4=300-4=296 \\
71 \times 8 \not= 296 \\
f(5) \times f(2) \not= f(10) \\
\hbox{statement 4 is false}$

Stamement 2. f(-2)=f(2) is true.

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3 years ago

Y + 7 = 4(x + 2)<br> Write in standard form.

rjkz [21]

This you answer for sure