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3 years ago

Evaluate ƒ(x) when x = -9. A. No solution B. 488 C. 12 D. 110

Mathematics

1 answer:

kondaur [170]3 years ago

6 0

Answer:

The answer to your question is: 12

Step-by-step explanation:

You have a function with two conditions,

- the first condition do not consider number nine, because it uses the symbol <, then we can not evaluate nine in this function.

- the second condition considers nine because uses the symbol ≤ which means that nine is considered here, but the function equals 12, so that is the solution.

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Can somebody help me with this?

Natasha_Volkova [10]

Step-by-step explanation:

Hey there!

By looking through figure, l and m are parallel lines and a transversal line passes through the lines.

Now,

7x + 12° = 12x - 28°( alternate angles are equal)

12°+28° = 12x - 7x

40° = 5x

$x = \frac{40}{5}$

Therefore, x = 8°

Now,

12x - 28° + 9y - 77 = 180° ( being linear pair)

12×8° - 28° + 9y -77° = 180°

96° - 28° + 9y - 77° = 180°

-9 + 9y = 180°

9y = 180° + 9°

y = 189°/9

Therefore, y = 21°

Therefore, X = 8° and y= 21° .

Hope it helps....

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3 years ago

Determine the point on the graph of the linear equation 2x + 5y = 19, whose ordinate is 1 1/2 times its abscissa.

rosijanka [135]

Answer:

(2, 3)

Step-by-step explanation:

2x + 5y = 19

5y = -2x + 19

y = $-\frac{2}{5} x + \frac{19}{5}$

P(abscissa, ordinate)

P(x, 1.5x)

P(2, 3)

$3 = -\frac{2}{5} (2) + \frac{19}{5}$

$3 = -\frac{4}{5} + \frac{19}{5}$

3 = 15/5

3 = 3

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