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3 years ago

Evaluate ƒ(x) when x = -9. A. No solution B. 488 C. 12 D. 110

Mathematics

1 answer:

kondaur [170]3 years ago

6 0

Answer:

The answer to your question is: 12

Step-by-step explanation:

You have a function with two conditions,

- the first condition do not consider number nine, because it uses the symbol <, then we can not evaluate nine in this function.

- the second condition considers nine because uses the symbol ≤ which means that nine is considered here, but the function equals 12, so that is the solution.

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4 years ago

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3 years ago

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Simplify (12a^{5}-6a-10a^{3})-(10a-2a^{5}-14a^{4})(12a 5 −6a−10a 3 )−(10a−2a 5 −14a 4 ) . Write the answer in standard form

Katen [24]

Answer:

$(12a^{5}-6a-10a^{3})-(10a-2a^{5}-14a^{4}) = 14a^{5}+14a^{4}-10a^{3}-16a$

Step-by-step explanation:

Given

$(12a^{5}-6a-10a^{3})-(10a-2a^{5}-14a^{4})$

Required

Simplify

We have:

$(12a^{5}-6a-10a^{3})-(10a-2a^{5}-14a^{4})$

Open brackets

$12a^{5}-6a-10a^{3}-10a+2a^{5}+14a^{4}$

Collect like terms

$12a^{5}+2a^{5}+14a^{4}-10a^{3}-6a-10a$

$14a^{5}+14a^{4}-10a^{3}-16a$

Hence:

$(12a^{5}-6a-10a^{3})-(10a-2a^{5}-14a^{4}) = 14a^{5}+14a^{4}-10a^{3}-16a$

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3 years ago

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