When you divide two fractions, you do Keep, Change, Flip or KCF. So you keep the 3/5, you change the division sign to a multiplication sign, then flip the 3/15 to 15/3. So the new equation is 3/5x15/3. Then you simply the two sides so it becomes 1/1x3/1.....
Meaning the answer is 3.
g(x) = 12(2)x - 1
h(x) = 3x
We are looking for this :
g(6) * h(6) ....so we have....
12(2)6-1 * 36 =
12(2)5 * 729 =
12*32 * 729 = 279,936 points
Area of parallelogram<span>=</span><span>base x </span><span>height
Given :
Base = 12 in.
Height = 3 in.
Hence,
Area = 12 x 3
= 36 in. square</span>
Answer:
D. $31,337.27
Step-by-step explanation:
We have that the initial amount of the loan is $5500.
Miranda took the loan for 4 years. So, the total present value is $5500×4 = $22,000.
The rate of interest on the loan is 7.5% i.e. 0.075 and it was for the duration of 10 years.
Also, it is given that the loan was compounded annually.
We have the formula as,

i.e. ![PV=\frac{P\times [1-(1+\frac{r}{n})^{-t\times n}]}{\frac{r}{n}}](https://tex.z-dn.net/?f=PV%3D%5Cfrac%7BP%5Ctimes%20%5B1-%281%2B%5Cfrac%7Br%7D%7Bn%7D%29%5E%7B-t%5Ctimes%20n%7D%5D%7D%7B%5Cfrac%7Br%7D%7Bn%7D%7D)
Substituting the values, we get,
i.e. ![PV=\frac{P\times [1-(1+\frac{0.075}{12})^{-10\times 12}]}{\frac{0.075}{12}}](https://tex.z-dn.net/?f=PV%3D%5Cfrac%7BP%5Ctimes%20%5B1-%281%2B%5Cfrac%7B0.075%7D%7B12%7D%29%5E%7B-10%5Ctimes%2012%7D%5D%7D%7B%5Cfrac%7B0.075%7D%7B12%7D%7D)
i.e. ![22000=\frac{P\times [1-(1+0.00625)^{-120}]}{0.00625}](https://tex.z-dn.net/?f=22000%3D%5Cfrac%7BP%5Ctimes%20%5B1-%281%2B0.00625%29%5E%7B-120%7D%5D%7D%7B0.00625%7D)
i.e. ![22000=\frac{P\times [1-(1.00625)^{-120}]}{0.00625}](https://tex.z-dn.net/?f=22000%3D%5Cfrac%7BP%5Ctimes%20%5B1-%281.00625%29%5E%7B-120%7D%5D%7D%7B0.00625%7D)
i.e. ![22000=\frac{P\times [1-0.4735]}{0.00625}](https://tex.z-dn.net/?f=22000%3D%5Cfrac%7BP%5Ctimes%20%5B1-0.4735%5D%7D%7B0.00625%7D)
i.e. 
i.e. 
i.e. 
i.e. 
Thus, the total lifetime cost to pay of the loans compounded annually = 261.16 × 120 = $31,339.2
Hence, the total cost close to the answer is $31,337.27
A proportional relationship is a relationship between variables such that the amount of one variable is a multiple of the other variable
A table showing the amount of sugar in different sizes of orange juice is presented as follows;
![\begin{array}{|c|cc|}\mathbf{Amount \ of \ orange \ juice, \ x}&&\mathbf{Quantity \ of \, sugar\ (g), \ f(x)}\\3&&8.25\\6&&16.5\\9&&24.75\\12&&33\\15&&41.25\end{array}\right]](https://tex.z-dn.net/?f=%5Cbegin%7Barray%7D%7B%7Cc%7Ccc%7C%7D%5Cmathbf%7BAmount%20%5C%20of%20%5C%20orange%20%5C%20juice%2C%20%5C%20x%7D%26%26%5Cmathbf%7BQuantity%20%5C%20of%20%5C%2C%20sugar%5C%20%28g%29%2C%20%5C%20f%28x%29%7D%5C%5C3%26%268.25%5C%5C6%26%2616.5%5C%5C9%26%2624.75%5C%5C12%26%2633%5C%5C15%26%2641.25%5Cend%7Barray%7D%5Cright%5D)
Reason:
The given parameter are;
12 ounces of orange juice contains 33 grams of sugar
Therefore, we have;
The amount of sugar per ounce of orange juice is given as follows;

Therefore, there are 2.75 grams of sugar per ounce of orange juice
which gives;
The amount of sugar in different sizes of orange juice, f(x) = 2.75·x
Where <em>x</em> represents the amount of orange juice, and f(x) represents the amount of sugar in the orange juice
A table showing the amount of sugar present in different sizes of orange juice is given as follows;
![\begin{array}{|c|cc|}\mathbf{Amount \ of \ orange \ juice, \ x}&&\mathbf{Quantity \ of \, sugar\ (g), \ f(x)}\\3&&8.25\\6&&16.5\\9&&24.75\\12&&33\\15&&41.25\end{array}\right]](https://tex.z-dn.net/?f=%5Cbegin%7Barray%7D%7B%7Cc%7Ccc%7C%7D%5Cmathbf%7BAmount%20%5C%20of%20%5C%20orange%20%5C%20juice%2C%20%5C%20x%7D%26%26%5Cmathbf%7BQuantity%20%5C%20of%20%5C%2C%20sugar%5C%20%28g%29%2C%20%5C%20f%28x%29%7D%5C%5C3%26%268.25%5C%5C6%26%2616.5%5C%5C9%26%2624.75%5C%5C12%26%2633%5C%5C15%26%2641.25%5Cend%7Barray%7D%5Cright%5D)
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