Answer:
The answer is
4.1 units
Step-by-step explanation:
The distance between two points can be found using the formula
<h3>
</h3>
where
( x1 , y1) and ( x2 , y2) are the points
From the question
The points are (6, -1) and (5, 3)
The distance between the points is
<h3>
</h3><h3>
</h3><h3>
</h3><h3>
</h3>
<h3 />
= 4.123105
We have the final answer as
<h3>4.1 units</h3>
Hope this helps you
A graphic scale is a ruler printed on the map and is used to convert distances on the map to actual ground distances. The graphic scale is divided into two parts. To the right of the zero, the scale is marked in full units of measure and is called the primary scale. To the left of the zero, the scale is divided into tenths and is called the
extension scale.
4 cupcakes because if you do 12/ 1/.. you do kcf = to 12 x 1/3= 4
your welcome
Answer:
a^3 + b^3
Step-by-step explanation:
(a + b)(a^2-ab+b^2)
a(a^2 -ab +b^2) +b(a^2-ab+b^2)
a^3 - a^2b +ab^2 + ba^2 -ab^2 +b^3
a^3 -a^2b +a^2b ab^2-ab^2 + b^3
The final answer will then be:
a^3 + b^3
Hope this helps! Have a great one! And I give out the best of luck for whatever quiz this is on!
Answer:
A volcano ejected with an initial velocity of 304 feet per second.
The height in feet is given by the equation H=-16t^2+ 304t where t is the time in seconds.
We will use the equation that traces the path of the projectile to determine the following information:
1) The time it takes the projectile to reach its maximum height (using the vertex formula: t=-b/2a)
The equation; H = -16t^2 + 304t, a=-16; b=304
t = -304/2°(-16)
t = 9.5 sec to reach max height
2) The maximum height of the projectile (use the result from part 1 to find the maximum height of the projectile)
t = 9.5
H = -16(9.5^2) + 304(9.5)
h = = -1444 + 2888
h = 1444 ft is the max height
3) Find the time it takes the projectile to return to the ground. Assume that the projectile starts at height H=0.
-16t^2 + 304t = 0
factor out -16t
-16t(t - 19) = 0
t = 19 sec to reach the ground
Step-by-step explanation:
