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valina [46]
3 years ago
7

THIS IS EASY!! PLS HELP ME! ASAP PLS

Mathematics
2 answers:
andrew-mc [135]3 years ago
6 0

Answer:

it’s actually b not a

Step-by-step explanation:

took the test :)

DanielleElmas [232]3 years ago
3 0

Answer:

A

Step-by-step explanation:

I Hope this helps you out!

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0.546 = 0.4 + ? + 0.006<br> Please Explain the Answer to me!
nadya68 [22]

Answer:  ? = 0.14

Step-by-step explanation:

So you need to find the value that fits the question mark. This means you have to get it by itself.

To start you subtract 0.4 from 0.546, which equals .146. Then you subtract 0.006 from 0.146 to get 0.14

What it looks like mathematically :

0.546 = 0.4 + ? + 0.006  

0.146= ? + 0.006  

0.14=?

Hopes this helps :)

5 0
3 years ago
What's 6253 divided by 71
Stella [2.4K]
6253/71 = 88.07 thats the answer :)))
i hope this is helpful 
have a nice day 
3 0
3 years ago
Read 2 more answers
If discount rate is 12%, the present value of Rs X recieved at the end of each year for the next five years is equal to
myrzilka [38]

Answer:

Present Value = X [\frac{1}{(1 + 0.12)^{1} }  + \frac{1}{(1 + 0.12)^{2} }  + \frac{1}{(1 + 0.12)^{3} }  + \frac{1}{(1 + 0.12)^{4} }  + \frac{1}{(1 + 0.12)^{5} } ]

Step-by-step explanation:

To find - If discount rate is 12%, the present value of Rs X received at the end of each year for the next five years is equal to .... ?

Solution -

We know that, formula for finding the Present vale is given by

Present value = Future value / (1 + r)ⁿ

where r is the rate of interest

and n is Number of periods

Now,

Here in the question, we have

r = 12% = 12/100 = 0.12

n = 5

Also, Given that, we have received Rs X at the end of each year

So,

Present Value = \frac{X}{(1 + 0.12)^{1} }  + \frac{X}{(1 + 0.12)^{2} }  + \frac{X}{(1 + 0.12)^{3} }  + \frac{X}{(1 + 0.12)^{4} }  + \frac{X}{(1 + 0.12)^{5} }

                        = X [\frac{1}{(1 + 0.12)^{1} }  + \frac{1}{(1 + 0.12)^{2} }  + \frac{1}{(1 + 0.12)^{3} }  + \frac{1}{(1 + 0.12)^{4} }  + \frac{1}{(1 + 0.12)^{5} } ]

⇒Present Value = X [\frac{1}{(1 + 0.12)^{1} }  + \frac{1}{(1 + 0.12)^{2} }  + \frac{1}{(1 + 0.12)^{3} }  + \frac{1}{(1 + 0.12)^{4} }  + \frac{1}{(1 + 0.12)^{5} } ]

7 0
3 years ago
The graph of f(x) = 2x + 3 shifts 10 units to the right when it is replaced with the graph of f(x) = 2x − k. What is the value o
tangare [24]

Answer:

10

Step-by-step explanation:

k represents how many places the graph will be shifted. -k means that is being shifted to the right and positive means being shifted to the left.

So when moving 10 units to the right, k will equal 10

7 0
3 years ago
All of the following expressions have the same value, when x = -2 and y = 4, except _____.
irinina [24]

Answer:

C

Step-by-step explanation:

When plugged in it is -4(-2)² which equals -16 while the others equal 16

4 0
4 years ago
Read 2 more answers
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