The probability distribution for a
1 answer:
Note: The values in the table are not correct because the sum of the probability of all events is not equal to one. The should be 0.13 and 0.33 instead of 0.113 and 0.133 respectively.
Given:
The probability distribution for a random variable x is given in the table.
x : -5 -3 -2 0 2 3
P(x) : 0.17 0.13 0.33 0.16 0.11 0.10
To find:
The probability of -2.
Solution:
From the given probability distribution for a random variable x, it is clear that the value of the probability is 0.33 corresponding to -2.
Therefore, the probability of -2 is 0.33.
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Answer:
1) Domain: { 1,2,3,4,5,6}
Range: {12,24,36,48,60,72}
2) First four terms are: 2,5,8,11
3) First four terms are: 8,13,20,29
4) First four terms are: 0,0,2,6
5) First four terms are: 0,1,1.41,1.73
Step-by-step explanation:
1.
n 1 2 3 4 5 6
f(n) 12 24 36 48 60 72
Domain: { 1,2,3,4,5,6}
Range: {12,24,36,48,60,72}
Write first four terms of each sequence
2) f(n)=3n-1
Put n = 1, 3(1)-1 = 3-1 = 2
Put n = 2, 3(2)-1 = 6-1 = 5
Put n = 3, 3(3)-1 = 9-1 = 8
Put n = 4, 3(4)-1 = 12-1 = 11
So, First four terms are: 2,5,8,11
3) f(n)=n^2+2n+5
Put n = 1, (1)^2+2(1)+5= 1+2+5 = 8
Put n = 2, (2)^2+2(2)+5 = 4+4+5= 13
Put n = 3, (3)^2+2(3)+5 = 9+6+5 = 20
Put n = 4, (4)^2+2(4)+5 = 16+8+5 = 29
So, First four terms are: 8,13,20,29
4) f(n)=(n-1)(n-2)
Put n = 1, (1-1)(1-2) = 0(-1) = 0
Put n = 2, (2-1)(2-2) = 1(0) = 0
Put n = 3, (3-1)(3-2) = 2(1) = 2
Put n = 4, (4-1)(4-2) = 3(2) = 6
So, First four terms are: 0,0,2,6
5) f(n) =
Put n=1
Put n=2
Put n=3
Put n=4
So, First four terms are: 0,1,1.41,1.73