Question

What is the distance between pints (-2 -5) and (3 -6)

Answer 1

Answer:

$\displaystyle d = \sqrt{26}$

General Formulas and Concepts:

Pre-Algebra

Order of Operations: BPEMDAS

1. Brackets
2. Parenthesis
3. Exponents
4. Multiplication
5. Division
6. Addition
7. Subtraction

• Left to Right

Algebra II

• Distance Formula: $\displaystyle d = \sqrt{(x_2-x_1)^2+(y_2-y_1)^2}$

Step-by-step explanation:

Step 1: Define

Point (-2, -5)

Point (3, -6)

Step 2: Find distance d

Simply plug in the 2 coordinates into the distance formula to find distance d

1. Substitute in points [DF]:                     $\displaystyle d = \sqrt{(3--2)^2+(-6--5)^2}$
2. (Parenthesis) Simplify:                         $\displaystyle d = \sqrt{(3+2)^2+(-6+5)^2}$
3. (Parenthesis) Add:                               $\displaystyle d = \sqrt{(5)^2+(-1)^2}$
4. [√Radical] Exponents:                         $\displaystyle d = \sqrt{25+1}$
5. [√Radical] Add:                                    $\displaystyle d = \sqrt{26}$