Is the square root of 19 equal to 4.358

A cow ate 38 pounds of grass, the cow now weighs 394 pounds. How much would the cow weigh if it did not eat the grass?

MrRa [10]

The cow before eating will weigh 352 pounds

7 0

3 years ago

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What happens when a line segment is dilated from a point on the line?

irina [24]

Answer:

Step-by-step explanation:

Concept 3: The dilation of a line segment is longer or shorter in the ratio given by the scale factor. If the scale factor is greater than 1 (k > 1), the image will be larger than the pre-image, making the segments (sides) of the image longer than the corresponding sides of its pre-image (an enlargement).

3 0

2 years ago

A particle moves according to a law of motion s = f(t), t ? 0, where t is measured in seconds and s in feet.

Usimov [2.4K]

Answer:

a) $\frac{ds}{dt}= v(t) = 3t^2 -18t +15$

b) $v(t=3) = 3(3)^2 -18(3) +15=-12$

c) $t =1s, t=5s$

d) $[0,1) \cup (5,\infty)$

e) $D = [1 -9 +15] +[(5^3 -9* (5^2)+ 15*5)-(1-9+15)]+ [(6^3 -9(6)^2 +15*6)-(5^3 -9(5)^2 +15*5)] =7+ |32|+7 =46$

And we take the absolute value on the middle integral because the distance can't be negative.

f) $a(t) = \frac{dv}{dt}= 6t -18$

g) The particle is speeding up $(1,3) \cup (5,\infty)$

And would be slowing down from $[0,1) \cup (3,5)$

Step-by-step explanation:

For this case we have the following function given:

$f(t) = s = t^3 -9t^2 +15 t$

Part a: Find the velocity at time t.

For this case we just need to take the derivate of the position function respect to t like this:

$\frac{ds}{dt}= v(t) = 3t^2 -18t +15$

Part b: What is the velocity after 3 s?

For this case we just need to replace t=3 s into the velocity equation and we got:

$v(t=3) = 3(3)^2 -18(3) +15=-12$

Part c: When is the particle at rest?

The particle would be at rest when the velocity would be 0 so we need to solve the following equation:

$3t^2 -18 t +15 =0$

We can divide both sides of the equation by 3 and we got:

$t^2 -6t +5=0$

And if we factorize we need to find two numbers that added gives -6 and multiplied 5, so we got:

$(t-5)*(t-1) =0$

And for this case we got $t =1s, t=5s$

Part d: When is the particle moving in the positive direction? (Enter your answer in interval notation.)

For this case the particle is moving in the positive direction when the velocity is higher than 0:

$t^2 -6t +5 >0$

$(t-5) *(t-1)>0$

So then the intervals positive are $[0,1) \cup (5,\infty)$

Part e: Find the total distance traveled during the first 6 s.

We can calculate the total distance with the following integral:

$D= \int_{0}^1 3t^2 -18t +15 dt + |\int_{1}^5 3t^2 -18t +15 dt| +\int_{5}^6 3t^2 -18t +15 dt= t^3 -9t^2 +15 t \Big|_0^1 + t^3 -9t^2 +15 t \Big|_1^5 + t^3 -9t^2 +15 t \Big|_5^6$

And if we replace we got:

$D = [1 -9 +15] +[(5^3 -9* (5^2)+ 15*5)-(1-9+15)]+ [(6^3 -9(6)^2 +15*6)-(5^3 -9(5)^2 +15*5)] =7+ |32|+7 =46$

And we take the absolute value on the middle integral because the distance can't be negative.

Part f: Find the acceleration at time t.

For this case we ust need to take the derivate of the velocity respect to the time like this:

$a(t) = \frac{dv}{dt}= 6t -18$

Part g and h

The particle is speeding up $(1,3) \cup (5,\infty)$

And would be slowing down from $[0,1) \cup (3,5)$

5 0

3 years ago

PLEASE HELP ASAP THE DETAILS ARE BELOW.What is the value of x?

Aloiza [94]

Answer:

x = 30°.

Step-by-step explanation:

The dashes on the three lines indicate that the three lines are of equal lengths. The smaller triangle made out of the three lines (the one with two vertices on the circumference of the circle and one at the center of the circle) is an isosceles triangle. All three of the triangle's interior angles are 60° since it is isosceles.

The line (the one with arrows on its ends) touches the circle at only one point. That line is a tangent to the circle. That line is perpendicular to the segment that connects the center of the circle to the point of tangency. The angle between the two will be 90°.

The largest triangle includes three angles:

The angle with the center of the circle as its vertice: 60°;
The right angle due to the tangent to the circle: 90°;
The angle x°.

What is the value of x?

The three interior angles of a triangle add up to 180°. As a result,

60° + 90° + x° = 180°

x = 180 - 90 - 60 = 30.

6 0

3 years ago

How to I write 1/8 without using a fraction bar ( it wants me to use exponents)

oksano4ka [1.4K]

2^-3

two raised to negative three

6 0

3 years ago

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