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MissTica
3 years ago
14

1. Which expression shows the prime factorization of 48? A. 2 To The 4th Power x 3 B. 2 To The 3rd Power x 3 To The 2nd Power C.

4 x 12 D. 24 To The 2nd Power
Mathematics
1 answer:
Sergio039 [100]3 years ago
6 0
Answer: A

Explanation:
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WILL GIVE BRAINLIEST 2 hours x 47 mph please show work for brainliest
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Answer:

2 hours * (47 miles / hour) = 94 miles

multiply the value in miles per hour by the conversion factor '1.609344'.

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Step-by-step explanation:

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4 years ago
Scientific notation is good way to write what numbers
OLEGan [10]

It’s a great way to write numbers that are very big numbers or very small numbers.

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A. The cost of no bags of kettle corn. With no bags, there will be no cost.
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3 years ago
Read 2 more answers
NEED HELP ASAP PLEASE!!
qwelly [4]

Option D:

$y=\frac{5x-2}{x}

Solution:

Given function:

$y=\frac{-2}{x-5}

To find the inverse of the function.

<u>Inverse of a function:</u>

<em>If a function f(x) is mapping x to y, then the inverse function of f(x) maps y back to x.</em>

$y=\frac{-2}{x-5}

Interchange the variables x and y.

$x=\frac{-2}{y-5}

Now, solve for y.

Multiply both sides by (y - 5).

$x(y-5)=-\frac{2}{y-5}(y-5)

Cancel the common factors, we get

x(y-5)=-2

Divide by x on both sides.

$y-5=-\frac{2}{x}

Add 5 on both sides.

$y=-\frac{2}{x}+5

$y=-\frac{2}{x}+\frac{5}{1}

To make the denominator same, multiply the 2nd term by \frac{x}{x}.

$y=-\frac{2}{x}+\frac{5x}{x}

$y=\frac{-2+5x}{x}

$y=\frac{5x-2}{x}

Option D is the correct answer.

8 0
3 years ago
Find the equation of the parabola that passes through
valentinak56 [21]

so we have the points of (0,-7),(7,-14),(-3,-19), let's plug those in the y = ax² + bx + c form, since we have three points, we'll plug each one once, thus a system of three variables, and then we'll solve it by substitution.

\bf \begin{array}{cccllll} \stackrel{\textit{point (0,-7)}}{-7=a(0)^2+b(0)+c}& \stackrel{point (7,-14)}{-14=a(7)^2+b(7)+c}& \stackrel{point (-3,-19)}{-19=a(-3)^2+b(-3)+c}\\\\ -7=c&-14=49a+7b+c&-19=9a-3b+c \end{array}

well, from the 1st  equation, we know what "c" is already, so let's just plug that in the 2nd equation and solve for "b".

\bf -14=49a+7b-7\implies -7=49a+7b\implies -7-49a=7b \\\\\\ \cfrac{-7-49a}{7}=b\implies \cfrac{-7}{7}-\cfrac{49a}{7}=b\implies -1-7a=b

well, now let's plug that "b" into our 3rd equation and solve for "a".

\bf -19=9a-3b-7\implies -12=9a-3b\implies -12=9a-3(-1-7a) \\\\\\ -12=9a+3+21a\implies -15=9a+21a\implies -15=30a \\\\\\ -\cfrac{15}{30}=a\implies \blacktriangleright -\cfrac{1}{2}=a \blacktriangleleft \\\\[-0.35em] ~\dotfill\\\\ \stackrel{\textit{and since we know that}}{-1-7a=b}\implies -1-7\left( -\cfrac{1}{2} \right)=b\implies -1+\cfrac{7}{2}=b\implies \blacktriangleright \cfrac{5}{2}=b \blacktriangleleft \\\\[-0.35em] \rule{34em}{0.25pt}\\\\ ~\hfill y=-\cfrac{1}{2}x^2+\cfrac{5}{2}x-7~\hfill

3 0
3 years ago
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