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3 years ago

Find the median of the set of data. Use a calculator if necessary. (Remember to put the list in numerical order.)

Mathematics

2 answers:

e-lub [12.9K]3 years ago

6 0

Answer:

median is 9

Step-by-step explanation:

to find median u must arrange the data from ascending to descending order.

6 , 7 , 9 , 12 , 13

median = N + 1/2 (N means no of data)

= 5 + 1/2

= 6/2

= 3 th term

= 9

GalinKa [24]3 years ago

5 0

Answer:

Step-by-step explanation:

To find the median of a set of data, arrange the data by value:

6, 7, 9, 12, 13

The number in the middle is the median.

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20 = x/4 - 13 help plz thank you

murzikaleks [220]

Answer: x = 132 daw

Step-by-step explanation: believe me

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3 years ago

Read 2 more answers

Convert 1 cal/(m^2 * sec * °C) into BTU/(ft^2 * hr * °F)

Crazy boy [7]

Answer:

$1\ \frac{\text{cal}}{m^2\times sec\times ^\circ C}=0.03926\frac{\text{BTU}}{ft^2\times hr\times ^\circ F}$

Step-by-step explanation:

To find : Convert $1\ \frac{\text{cal}}{m^2\times sec\times ^\circ C}$ into $\frac{\text{BTU}}{ft^2\times hr\times ^\circ F}$

Solution :

We convert units one by one,

$1\text{ m}^2=10.7639\text{ ft}^2$

$1\text{ sec}=\frac{1}{3600}\text{ hour}$

$1\text{ cal}=0.003968\text{ BTU}$

Converting temperature unit,

$^\circ C\times \frac{9}{5}+32=^\circ F$

$1^\circ C\times \frac{9}{5}+32=33.8^\circ F$

So, $1^\circ C=33.8^\circ F$

Substitute all the values in the unit conversion,

$1\ \frac{\text{cal}}{m^2\times sec\times ^\circ C}=\frac{0.003968}{10.7639\times \frac{1}{3600}\times 33.8}\frac{\text{BTU}}{ft^2\times hr\times ^\circ F}$

$1\ \frac{\text{cal}}{m^2\times sec\times ^\circ C}=\frac{0.003968}{0.101061}\frac{\text{BTU}}{ft^2\times hr\times ^\circ F}$

$1\ \frac{\text{cal}}{m^2\times sec\times ^\circ C}=0.03926\frac{\text{BTU}}{ft^2\times hr\times ^\circ F}$

Therefore, The conversion of unit is $1\ \frac{\text{cal}}{m^2\times sec\times ^\circ C}=0.03926\frac{\text{BTU}}{ft^2\times hr\times ^\circ F}$

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3 years ago

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SpyIntel [72]

Can you show the mentioned diagram?

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3 years ago

HELP. It’s LOG form. Since were out of school I forgot how I did this and it’s due so it would be a life saver.

____ [38]

Answer:

see below

Step-by-step explanation:

exponent to log: $a^b$ = c ---> logₐc = b

ie. question 6

log ₁₀(3x+1) = 2 -----> $10^{2} = 3x+1$

that will get you through questions 1 to 3, 5 to 6, and 8

in question 4, all you have to do is know that 2^2 = 4 and 2^3 = 8, by setting the bases equal, you can manipulate the exponents to get 2x+8 = 3x-3

for questions 7 and 9,

remember that:

logₐc + logₐd = logₐ(cd)

logₐc - logₐd = logₐ( $\frac{c}{d}$ )

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3 years ago

Allison’s dog is 6 pounds more than 5 times the weight of Gail’s dog. What algebraic expression could you make to find (g) which

emmasim [6.3K]

Given that Allison’s dog is 6 pounds more than 5 times the weight of Gail’s dog, it is important to know the following:

1. The word "more" indicates an Addition.

2. The word "times" indicates Multiplication.

Knowing this, you can write the following expression to represent "5 times the weight of Gail’s dog", where "g" is the weight of Gail’s dog:

$5g$

Therefore, you can determine that the weight of Allison's dog (in pounds) is the sum of 6 pounds and 5 times the weight of Gail's dog (in pounds). Then, you can represent this with this algebraic expression:

$5g+6$

Hence, the answer is:

$5g+6$

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10 months ago