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3 years ago

13

PLZ HELP ASAP!!!!!!!! WILL MARK YOU BRAINLIEST THX!

1 answer:

anygoal [31]3 years ago

7 0

Answer:

The first question is the third choice. Divide by two to get proper squaring. Anytime there is a number in front of the x in a situation like that, always divide by that number on both sides first. Then go from there.

The second question is also the third choice. The square root of 64 is 8. It can't be negative because square rooting is always positive unless you want a weird "i" in there. That's for algebra 2 and beyond so don't worry about it mate.

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miskamm [114]

Answer:

2

Step-by-step explanation:

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inna [77]

Answer:

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Step-by-step explanation:

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3 years ago

Divide -2x^3-5x^2+4x+2 by x+2

erik [133]

<u>Answer</u><u>: </u>

The correct option is C. $-2x^2-x+6, R(-10)$

<u> Explanation: </u>

<u>Given:</u>

Dividend = -2x^3-5x^2+4x+2

Divider =(x+2)

<u>Solution</u>:

Now by using the division method , we will find out the quotient and remainder of the given equation

And the equation will become

$-2x^3-5x^2+4x+2=(x+2)(-2x^2-x+6)-10$

So , We will get the quotient = $-2x^2-x+6$

And Remainder = -10

Hence the Correct option which perfectly satisfy the given equation is C.

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2 years ago

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jolli1 [7]

Answer:

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Step-by-step explanation:

52 times 2 equals 104

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3 years ago