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2 years ago

Enlarge the triangle by scale factor -1/3 with centre (-1,2)

Mathematics

1 answer:

Scorpion4ik [409]2 years ago

5 0

Answer:

All the sides of the triangle X'Y'Z' are twice as long as the sides of the original triangle XYZ. The triangle XYZ has been enlarged by a scale factor of 2.

All the sides of the triangle X'Y'Z' are twice as long as the sides of the original triangle XYZ. The triangle XYZ has been enlarged by a scale factor of 2.Enlargement is an example of a transformation. A transformation is a way of changing the size or position of a shape.To enlarge a shape, a centre of enlargement is required. When a shape is enlarged from a centre of enlargement, the distances from the centre to each point are multiplied by the scale factor.

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Someone please help me out with these questions . I don’t get them at all.

iVinArrow [24]

Answer:

a)similar; b)similar; c)similar; d)NOT similar

Step-by-step explanation:

>In general if

all corresponding angels are ≅, and

all corresponding sides are in proportion

then the Δs are similar

>we have 3 similarity theorems AA, SSS, and SAS

we can use that sum of angles in a triangle is 180 to find the missing angles

180-96-32 = 52

so in the smaller triangle the angles are 96°-52°-32°

in the larger triangle the angles given are 52°-32°

Since there are 2 corresponding angles congruent, AA theorem of similarity says that the 2 triangles are similar. The transformations were that the big triangle was shrunk and rotated

here we are given a pair of congruent angles and we need to check if the sides are in proportion, is 14/44.8 equal to 20/64?

14/44.8 =.3125 is equal to 20/64=.3125

since we have two corresponding sides in proportion and the angles in between them congruent the SAS theorem says that the 2 triangles are similar. The transformation was that the small triangle was dilated.

because we are given the 2 angles are congruent we can conclude that the lines NH and SL are parallel. NH║SL let us conclude that ∡H and ∡ L are congruent because 2 parallel lines cut by a transversal (ML in our case) form congruent angles. So ΔMNH is similar to ΔMSL because of AA theorem of similarity (one pair of A was given congruent, one other pair of A we concluded was congruent)

here we have to check if all the sides are in proportion to see if SSS theorem of similarity applies here

18/90 = .2

44/202.4≈.22

58.5/211.2≈.28

.2≠ .22 ≠ .28

since the sides are not in proportion the 2 triangles are NOT similar.

4 0

3 years ago

Dilations… please help I will give you brainless

DochEvi [55]

Answer:

The scale factor is 0.5

Step-by-step explanation:

Divide.

2/1=2

4/2=2

8/4=2

2/1=2

5/1.25=2

Now then, since this is a shrinking factor, divide 1 by the common outcome from the last section (2) to get 0.5

4 0

3 years ago

the angle θ is 7.2 degrees, and the circle arc s is 800 km. knowing that there are 360 degrees in a full circle what is the circ

kumpel [21]

The earth is 40000 kilometers around. There is no need to round off because the circumference already contains significant figures.

How do I calculate a circle's circumference?

A circle's diameter is multiplied by to determine its circumference (pi). You can also determine the circumference by multiplying 2radius by pi (=3.14).

Given: theta angle (central) = 7.2°; arc length S = 800 km

This indicates that an 800 km long arc is extending a circle with a 7.2° center angle ( earth in this case).

By definition, "An arc's length is a portion of a circle's diameter."

Therefore, we must first establish what percentage of the circle the specified arc length represents.

360° is a complete circle.

Thus, the fraction equals 7.2°/360°, or 1/50.

As a result, the stated arc length (800km) with a 7.2° central angle is 1/50th of the entire circle.

Thus, the whole circumference is 800 x 50, or 40000 km.

Alternately, you can calculate circumference using the formula below:

360° center angle x arc length as the circumference (theta)

Values substituted: circumference 800 = 360° 7.2°

circumference = 360°, 800°, and 7.2°, or 40000 kilometers