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PilotLPTM [1.2K]
3 years ago
9

The discount on a pack of socks is 15%. It is on sale for $17. What is the original price of the pack of socks?

Mathematics
1 answer:
Aneli [31]3 years ago
4 0

Answer:

$19.55

Step-by-step explanation:

17*0.15=2.55

17+2.55=19.55

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Find the width of a rectangular prism if the volume is 546cm, the height is 7cm and the length is 13cm.
Margaret [11]

7x w x 13=546

(7x13)*w= 546

91w=546

91w/91= 546/91

w= 6

the width is 6cm

7 0
3 years ago
Simplify 8^x/4^y x 2^z
Lera25 [3.4K]

Answer:

The answer is 8x.

Step-by-step explanation:

It is 8x.

EXCEPT,

Is it 2^{z} or 2^{2}

If it is 2^{z} then the answer is \frac{2^{3x+z} }{4}

PLEASE MARK BRAINLIEST

4 0
3 years ago
Help me asap ok thanks
Gre4nikov [31]

Answer: total profit = $418

======================================================

Work Shown:

June

Income = (4 lawns)*($27 per lawn) = $108

Expenses = ($32 for gas)+($12 for trim line) = $44

Profit = income - expenses = 108-44 = $64

----------------------------

July

Income = (12 lawns)*($20 per lawn) = $240

Expenses = ($89 for gas)+($29 for blade sharpening) = $118

Profit = income - expenses = 240 - 89 = $151

----------------------------

August

Income = (16 lawns)*($20 per lawn) = $320

Expenses = ($101 for gas)+($16 for oil) = $117

Profit = income - expenses = 320-117 = $203

----------------------------

Total profit = (june profit)+(july profit)+(august profit)

Total profit = (64) + (151) + (203)

Total profit = $418

If the final result was negative, then we would call this a loss. However, we have a positive value, so we go with a profit.

8 0
3 years ago
A consumer organization inspecting new cars found that many had appearance defects (dents, scratches, paint chips, etc.). While
Murljashka [212]

Answer:

The expected number of appearance defects in a new car  = 0.64

standard deviation = 0.93(approximately)

Step-by-step explanation:

Given -

7% had exactly three, 11% exactly two, and 21% only one defect in cars.

Let X be no of defects in a car

P(X=3) = .07 , P(X=2) = .11 , P(X=3) = .21

P(X=0 ) = 1 - .07 - .11 - .21 = 0.61

The expected number of appearance defects in a new car =

E(X) = \nu = = \sum X P(X) =3\times 0.07 + 2\times0.11 + 3\times0.21 + 0\times0.61 = 0.64

\sigma^{2}  = variation of E(X) = \sum (X - \nu) ^{2}P(X) = (3 - 0.64) ^{2}\times0.07 + (2 - 0.64) ^{2}\times0.11 + (1 - 0.64) ^{2}\times0.21 + (0 - 0.64) ^{2}\times0.61

 = (2.36) ^{2}\times0.07 + (1.36) ^{2}\times0.11 + (.36) ^{2}\times0.21 + ( 0.64) ^{2}\times0.61 = 0.8704

standard deviation  =  \sqrt{\sigma^{2}} = \sqrt{0.8704^{2}} = 0.93(approximately)

4 0
3 years ago
If (8^2)p = 8^4, what is the value of p?<br><br> 2<br> 3<br> 4<br> 6
Assoli18 [71]

Answer:

Step-by-step explanation:

8²p=8^4

64p=4096

p=64

p could also equal 2

8^2x2=8^4

3 0
2 years ago
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