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1 answer:
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Answer:
0.2
Step-by-step explanation:
If two number cubes as tossed then the total possible out comes are
Total = {(1,1),(2,1),(3,1),(4,1),(5,1),(6,1),(1,2),(2,2),(3,2),(4,2),(5,2),(6,2),(1,3),(2,3),(3,3),(4,3),(5,3),(6,3),(1,4),(2,4),(3,4),(4,4),(5,4),(6,4),(1,5),(2,5),(3,5),(4,5),(5,5),(6,5),(1,6),(2,6),(3,6),(4,6),(5,6),(6,6)}
Number of elements in sample space are
n(S)=36
Let A and B represent the following events.
A = The sum will be 4.
A = {(1,3),(2,2),(3,1)}
n(A) = 3
B = The sum is less than or equal to 6.
B = {(1,1),(1,2),(1,3),(1,4),(1,5),(2,1),(2,2),(2,3),(2,4),(3,1),(3,2),(3,3),(4,1),(4,2),(5,1)}
n(B)=15
Intersection of both events is
A∩B = {(1,3),(2,2),(3,1)}
n(A∩B) = 3
We need to find the probability that the sum will be 4, given that the sum is less than or equal to 6.
Therefore, the required probability is 0.2.