Examine the diagram, where BD is tangent to circle M at point D, and BA is secant to the same circle at points E and A.
1 answer:
Answer:
19 = x
Step-by-step explanation:
The square of the tangent segment = The product of (whole secant segment) (the outside part of the secant segment)
BD²= (BA)(BE)
8² = (4 + x - 7) (4) BA = BE + EB
8² = (x - 3)(4)
64 = 4x - 12
64 + 12 = 4x
76 = 4x
19 = x
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I got 3/8, hope this helps.
