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2 years ago

Examine the diagram, where BD is tangent to circle M at point D, and BA is secant to the same circle at points E and A.

Mathematics

1 answer:

Stella [2.4K]2 years ago

3 0

Answer:

19 = x

Step-by-step explanation:

The square of the tangent segment = The product of (whole secant segment) (the outside part of the secant segment)

BD²= (BA)(BE)

8² = (4 + x - 7) (4) BA = BE + EB

8² = (x - 3)(4)

64 = 4x - 12

64 + 12 = 4x

76 = 4x

19 = x

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