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masya89 [10]
2 years ago
7

17. Oranges cost 25 cents for 1/2 kilogram. How much would 8 kilograms of ornages cost? Show all of your work. Make sure to incl

ude your answer, proof, and evidence. PLZ NEED ASAP​
Mathematics
1 answer:
Debora [2.8K]2 years ago
5 0

9514 1404 393

Answer:

  $4.00

Step-by-step explanation:

We assume the price is proportional to the quantity of oranges. If p is the desired price in dollars, we want ...

  p/8 = 0.25/(1/2)

  p = 8(0.50) = 4.00 . . . . multiply by 8, simplify

8 kg of oranges would cost $4.00.

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Read 2 more answers
Please help me!!
ipn [44]

{\color{chartreuse}{Measure\:of\: ∠\:on\: one\: side\:of\:line\:=\:180°}}

∠ Given are (x + 18)° , x° , 4x° and one Angle is 90° as per diagram

Let ,

1st∠ = (x + 18)°

2nd∠ = x°

3rd∠ = 4x°

so ,

⟶\:(x \:+\: 18)°\:+\:x°\:+\: 4x°\:+\:90°\:=\:180°

⟶\:6x°\:+ \:18°\:+\:90°\:=\:180°

⟶\:6x°\:+ \:108°\:=\:180°

⟶\:6x°\:=\:180°\:-\:108°

⟶\:6x\:=\:72°

⟶\:x\:=\:\frac{72}{6} \\

⟶\:x\:=\:12°

substituting x = 12 at the place of x .

= x° + 18°

= 12° + 18 °

1st∠ = 30°

__________________________________

= x°

2nd∠ = 12°

__________________________________

= 4x°

= 4(12)°

3rd∠ = 48°

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2 years ago
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