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xeze [42]
3 years ago
15

6x+19+3x-6+5x-15=180​

Mathematics
2 answers:
Alinara [238K]3 years ago
5 0

Answer:

6x + 19 + 3x + -6 + 5x + -15 = 180

19 + -6 + -15 + 6x + 3x + 5x = 180

19 + -6 = 13

13 + -15 + 6x + 3x + 5x = 180

13 + -15 = -2

-2 + 6x + 3x + 5x = 180

6x + 3x = 9x

-2 + 9x + 5x = 180

9x + 5x = 14x

-2 + 14x = 180

-2 + 14x = 180

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '2' to each side of the equation.

-2 + 2 + 14x = 180 + 2

-2 + 2 = 0

0 + 14x = 180 + 2

14x = 180 + 2

180 + 2 = 182

14x = 182

Divide each side by '14'.

x = 13

x = 13

stich3 [128]3 years ago
3 0

6x+19+3x-6+5x-15=180

14x = 180 - 19 + 6 + 15

14x = 182

x = 182 : 14

x = 13

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\green{\large\underline{\sf{Solution-}}}

<u>Given expression is </u>

\rm :\longmapsto\:\dfrac{5 \times  {25}^{n + 1}  - 25 \times  {5}^{2n} }{5 \times  {5}^{2n + 3}  -  {25}^{n + 1} }

can be rewritten as

\rm \:  =  \: \dfrac{5 \times  { {(5}^{2} )}^{n + 1}  -  {5}^{2}  \times  {5}^{2n} }{5 \times  {5}^{2n + 3}  -  {( {5}^{2} )}^{n + 1} }

We know,

\purple{\rm :\longmapsto\:\boxed{\tt{  {( {x}^{m} )}^{n}  \: = \:   {x}^{mn}}}} \\

And

\purple{\rm :\longmapsto\:\boxed{\tt{ \:  \:   {x}^{m} \times  {x}^{n} =  {x}^{m + n} \: }}} \\

So, using this identity, we

\rm \:  =  \: \dfrac{5 \times  {5}^{2n + 2}  - {5}^{2n + 2} }{{5}^{2n + 3 + 1}  -  {5}^{2n + 2} }

\rm \:  =  \: \dfrac{{5}^{2n + 2 + 1}  - {5}^{2n + 2} }{{5}^{2n + 4}  -  {5}^{2n + 2} }

can be further rewritten as

\rm \:  =  \: \dfrac{{5}^{2n + 2 + 1}  - {5}^{2n + 2} }{{5}^{2n + 2 + 2}  -  {5}^{2n + 2} }

\rm \:  =  \: \dfrac{ {5}^{2n + 2} (5 - 1)}{ {5}^{2n + 2} ( {5}^{2}  - 1)}

\rm \:  =  \: \dfrac{4}{25 - 1}

\rm \:  =  \: \dfrac{4}{24}

\rm \:  =  \: \dfrac{1}{6}

<u>Hence, </u>

\rm :\longmapsto\:\boxed{\tt{ \dfrac{5 \times  {25}^{n + 1}  - 25 \times  {5}^{2n} }{5 \times  {5}^{2n + 3}  -  {25}^{n + 1} }  =  \frac{1}{6} }}

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