Find the value of x for m (arc AB)=23 and m(arc CD)=32 (the answer will be a decimal )

<img src="https://tex.z-dn.net/?f=%20%7B2%7D%5E%7Bx%7D%20%20%3D%208" id="TexFormula1" title=" {2}^{x} = 8" alt=" {2}^{x} = 8"

Marizza181 [45]

Hey there!

<h2>ANSWER: </h2>

Non linear

<h2>EXPLANATION:</h2>

Is $2^x=8$ linear or non-linear.

Since x has an exponent value that is equal to 2, it's non-linear. So that means $2^x=8$ is non-linear.

Hope this helps!

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7 0

3 years ago

Let U={1,2,3,4,5,6,7,8}A={2,3,6}B={2,4,5,7}C={1,7,8}Find the following use the roster method to write method to write the set. E

Ipatiy [6.2K]

A U B = set of all elements that are in both A or B:

A U B = {2, 3, 4, 5, 6, 7}

Here is a picture to see our answer.

6 0

11 months ago

a family has two cars. the first car has a fuel efficiency of 20 miles per gallon of gas and the second has a fuel efficiency of

nikklg [1K]

Car A consumes 25 gallon and car B consumes 15 gallon.

Step-by-step explanation:

Given,

The fuel efficiency of car A = 20 miles per gallon.

The fuel efficiency of car B = 15 miles per gallon.

In a week, two cars went 725 miles and consumed 40 gallons.

To find the consumption of each car in that week.

Let,

Car A consumed x gallon

Car B consumed y gallon.

According to the problem,

x+y = 40 ----- (1)

20x+15y = 725

or, 4x+3y = 145 -------- (2)

From (1) we get, x = 40-y

Putting the value of x in (2) we get,

4(40-y)+3y = 145

or, 160-4y+3y = 145

or, -y = 145-160

or, y = 15

From (1) we get, x = 40-15 = 25

Hence,

Car A consumes 25 gallon and car B consumes 15 gallon.

7 0

2 years ago

For f(x)=4sin(x2) between x=0 and x=3, find the coordinates of all intercepts, critical points, and inflection points to two dec

telo118 [61]

Answer:

Intercepts:

x = 0, y = 0

x = 1.77, y = 0

x = 2.51, y = 0

Critical points:

x = 1.25, y = 4

x = 2.17 , y = -4

x = 2.8, y = 4

Inflection points:

x = 0.81, y = 2.44

x = 1.81, y = -0.54

x = 2.52, y = 0.27

Step-by-step explanation:

We can find the intercept by setting f(x) = 0

$4sin(x^2) = 0$

$sin(x^2) = 0$

$x^2 = n\pi$ where n = 0, 1, 2,3, 4, 5,...

$x = \sqrt(n\pi)$

Since we are restricting x between 0 and 3 we can stop at n = 2

So the function f(x) intercepts at y = 0 and x:

x = 0

x = 1.77

x = 2.51

The critical points occur at the first derivative = 0

$f^{'}(x) = 4cos(x^2)2x = 8xcos(x^2) = 0$

$xcos(x^2) = 0$

$x = 0$ or

$cos(x^2) = 0$

$x^2 = \frac{\pi}{2} + n\pi$ where n = 0, 1, 2, 3

$x = \sqrt{\pi(n+1/2)}$

Since we are restricting x between 0 and 3 we can stop at n = 2

So our critical points are at

x = 1.25, $y = f(1.25) = 4sin(1.25^2) = 4$

x = 2.17 , $y = f(2.17) = 4sin(2.17^2) = -4$

x = 2.8, $y = f(2.8) = 4sin(2.8^2) = 4$

For the inflection point, we can take the 2nd derivative and set it to 0

$f^[''}(x) = 8(cos(x^2) - xsin(x^2)2x) = 8cos(x^2) - 16x^2sin(x^2) = 0$

$cos(x^2) = 2x^2sin(x^2)$

$tan(x^2) = \frac{1}{2x^2}$

We can solve this numerically to get the inflection points are at

x = 0.81, $y = f(0.81) = 4sin(0.81^2) = 2.44$

x = 1.81, $y = f(1.81) = 4sin(1.81^2) = -0.54$

x = 2.52, $y = f(2.52) = 4sin(2.52^2) = 0.27$

3 0

3 years ago

Please choose answer choice a,b,c or d

dmitriy555 [2]

Answer:

A. -4

Step-by-step explanation:

Slope is rise over run, or y2-y1 / x2-x1.

$\frac{y2-y1}{x2-x1} = \frac{-4-8}{2--1} =\frac{-12}{3} = -4$

<u>The slope is A. -4.</u>

Let's see--does that make sense? A slope of four would be pretty steep, and that matches the graph. It also should be negative because the line goes down and to the right, not up and to the right, so -4 makes sense!

4 0

3 years ago