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3 years ago

I need a little extra help with number three

Mathematics

1 answer:

diamong [38]3 years ago

6 0

Answer:

The answer to your question is:

Step-by-step explanation:

Data

f(x) = -2x² + 8x - 2

Process

-2x² + 8x = y + 2

-2(x² - 4x + 4) = y + 2 - 8

-2(x - 2)² = y - 6

(x - 2)² = 1/2 (y - 6)

Vertex = (2, 6)

Axis of symmetry = x = 2

y-intercept

f(0) = -2(0)² + 8(0) - 2

f(0) = 0 + 0 - 2

f(0) = -2

Domain (-∞, ∞)

Range (-∞, 6]

See the graph below

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Anyone know how to do this

adell [148]

Answer:

Final answer is $\frac{x^2-3x}{x^2-3x+2}$

Step-by-step explanation:

$\frac{x^2+x-6}{x^2+2x-3}+\frac{x-4}{x^2-3x+2}$

In this type of problems, we factor numerator and denominator whichever possible. then make denominators equal and combine numerator.

Then simplify to get the answer. $=\frac{x^2+x-6}{x^2+2x-3}+\frac{x-4}{x^2-3x+2}$

$=\frac{x^2+3x-2x-6}{x^2+3x-1x-3}+\frac{x-4}{x^2-1x-2x+2}$

$=\frac{x\left(x+3\right)-2\left(x+3\right)}{x\left(x+3\right)-1\left(x+3\right)}+\frac{x-4}{x\left(x-1\right)-2\left(x-1\right)}$

$=\frac{\left(x-2\right)\left(x+3\right)}{\left(x-1\right)\left(x+3\right)}+\frac{x-4}{\left(x-2\right)\left(x-1\right)}$

$=\frac{\left(x-2\right)}{\left(x-1\right)}+\frac{x-4}{\left(x-2\right)\left(x-1\right)}$

$=\frac{\left(x-2\right)}{\left(x-1\right)}\cdot\frac{\left(x-2\right)}{\left(x-2\right)}+\frac{x-4}{\left(x-2\right)\left(x-1\right)}$

$=\frac{x^2-2x-2x+4}{\left(x-1\right)\left(x-2\right)}+\frac{x-4}{\left(x-2\right)\left(x-1\right)}$

$=\frac{x^2-2x-2x+4+x-4}{\left(x-1\right)\left(x-2\right)}$

$=\frac{x^2-3x}{x^2-2x-1x+2}$

$=\frac{x^2-3x}{x^2-3x+2}$

Hence final answer is $\frac{x^2-3x}{x^2-3x+2}$

6 0

3 years ago

Read 2 more answers

WHO WANTS BRAINLIEST ??

lawyer [7]

Answer:

From what I can see I'd have to say y=2/3x-1.5 but I can't really tell what the exact y-intercept is.

Step-by-step explanation:

3 0

4 years ago

Plot on graph.

Rus_ich [418]

This equation is in vertex form so finding the vertex is easy.

Vertex: (-1,4)

Once you find the vertex, axis of symmetry is easy.

x=-1

Then find y intercept by finding h(0).

h(0)=(0+1)^2-4=-3

Now find x intercepts by solving for x when h(x)=0.

(x+1)^2-4=0

(x+1)^2=4

x+1=±2

x=±2-1

x=1,-3

7 0

3 years ago

Arrange the decimals from least to greatest. Choose the letter below that shows the order least to greatest.

Nonamiya [84]

Answer:

-4.3, -3.4, -0.43, -0.34, -0.043

7 0

3 years ago

Which one is the correct answer, thank u

miss Akunina [59]

Answer:

Step-by-step explanation:

The rule tells you that (x,y) -> (x + 1, y - 3), so you take each vertice and add one to the x-values, and subract 3 from the y-values.

(-6, 4) -> (-6 + 1, 4 - 3) which simplifies to (-5, 1)

(-3, -2) -> (-3 + 1, -2 - 3) which simplifies to (-2, -5)

(2, 1) -> (2 + 1, 1 - 3) which simplifies to (3, -2)

6 0

3 years ago