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3 years ago

Which best describes the scatter plot

2 answers:

7 0

D positive; non linear

4 0

I’m thinking probably letter D

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svetoff [14.1K]

Answer:

See attached diagram

Step-by-step explanation:

Triangle ABC has vertices A(9,3), B(-7,-5) and C(-3,7).

The dilation with a scale factor of 1/4 centered at (5, -5) has the rule

$(x,y)\rightarrow \left(\dfrac{1}{4}x+\dfrac{15}{4},\dfrac{1}{4}y-\dfrac{15}{4}\right)$

Then

$A(9,3)\rightarrow A'\left(\dfrac{1}{4}\cdot 9+\dfrac{15}{4},\dfrac{1}{4}\cdot 3-\dfrac{15}{4}\right)=A'(6,-3);$

$B(-7,-5)\rightarrow B'\left(\dfrac{1}{4}\cdot (-7)+\dfrac{15}{4},\dfrac{1}{4}\cdot (-5)-\dfrac{15}{4}\right)=B'(2,-5);$

$C(-3,7)\rightarrow C'\left(\dfrac{1}{4}\cdot (-3)+\dfrac{15}{4},\dfrac{1}{4}\cdot 7-\dfrac{15}{4}\right)=C'(3,-2).$

6 0

3 years ago

andrey2020 [161]

ANSWER. My answer might be wrong also.

5 0

3 years ago

Rzqust [24]

The probability that at least one of them will get scholarship is 0.93

<h3>How to determine the probability</h3>

The given parameters are:

P(Boy) = 0.75

P(Girl) = 0.72

The probability that at least one of them will get scholarship is calculated using

P = P(Boy only) or P(Girl only) or P(Both)

This is then calculated as:

P = 0.75 * (1 - 0.72) + 0.72 * (1 - 0.75) + 0.72 * 0.75

Evaluate the products

P = 0.21 + 0.18 + 0.54

Evaluate the sum

P = 0.93

Hence, the probability that at least one of them will get scholarship is 0.93