1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
sukhopar [10]
3 years ago
13

1. Jim jogs his morning route of 5 km in 25 minutes. He plans on running for an hour in

Mathematics
1 answer:
mylen [45]3 years ago
6 0

The time Jim runs in the evening compared to the morning time is: 60 minutes : 25 minutes = 2.4 times

At the same speed as in the morning, Jim will run a distance of: 5 x 2.4 = 12 km

You might be interested in
____________________​
enyata [817]

Answer:

107.5

Step-by-step explanation:

2x21.5/

3 0
3 years ago
Out of 1,000 people in a small town, 500 are members of a choir. Out of these 500 members in a choir, 100 are men. Out of the 50
Ad libitum [116K]
The correct answer is 25%
8 0
3 years ago
Read 2 more answers
Which system has (3,0) as a solution?
Elena L [17]

Answer:

x+y=3

Assuming that the option 1 and 2 dont mean anything

7 0
3 years ago
Please help I’m struggling with absolute equations!!
Artyom0805 [142]

Hi there! I'm actually just learning about absolute value equations right now, so I'll walk you through how to solve these types of problems, because I know they can get confusing.

______________________________________________________________

7. There is an error in the student work shown below: Solve |x - 1| - 3 = 5

The student split the equation into two equations. She split it into x - 1 - 3 = 5 or x - 1 - 3 = -5. We can already see there is an error in what the student did.

Before splitting your absolute value equation into two cases, a positive case and a negative case, you must make sure you isolate your absolute value.

The student should have added 3 to both sides to isolate |x - 1|. Since she did not do that, her work will be off because of her minor error.

Now let's solve for the actual answer. You have |x - 1| - 3 = 5. Let's not make the mistake that the student made, and add 3 to both sides of the equation to isolate the absolute value. Now you should have:

|x - 1| = 8

Split this absolute value equation into two cases, a positive case and a negative case. I assume you've learned about this. You can now remove the absolute value symbols. Your cases should look like:

x - 1 = 8 OR x - 1 = -8

Add 1 to both sides in both of the equations that you have made. Now you should have two answers to the absolute value problem, that should both work.

x = 9 OR x = -7; so the answer is x = 9, -7.

<em>--- Checking work ---</em>

I always check my work because sometimes absolute value equations do not hold true. Substitute 9 into the isolated absolute value equation.

|x - 1| = 8 becomes |(9) - 1| = 8

|(9) - 1| = 8 is true, because you solve inside the absolute value equation and you get 8 = 8, which is a true statement. Now let's substitute -7 into the isolated absolute value equation.

|x - 1| = 8 becomes |(-7) - 1| = 8

|(-7) - 1| = 8 is true, because you solve inside the absolute value equation and you get |-8| = 8, which is the same as 8 = 8, so it is a true statement. Both of the answers we got are valid answers.

______________________________________________________________

8. |6 - 4r| + 5 = 0

You know what to do first always, isolate the absolute value. Subtract 5 from both sides of the equation. Now you should have:

|6 - 4r| = -5

Now you can split this absolute value equation into two cases, which will be a positive case and a negative case. You can also remove the absolute value symbols. Now you should have:

6 - 4r = -5 OR 6 - 4r = 5

Subtract 6 from both sides of the equation in both of the equations. Rewrite your equation, and now you should have:

-4r = -11 OR -4r = -1

Divide both sides of the equation by -4 in both of the equations. After performing this operation, you should have both of your answers.

r = 11/4 OR r = 1/4

Substituting both answers will result in false statements, so that means your answer is no solution.

______________________________________________________________

9. |8 + Y| = 2Y - 3

Since the absolute value is already isolated, you know the drill, let's split the equation into two cases, one positive case and one negative case. Now you should have these two equations: (remember to add parentheses around the negative case since both numbers need to get multiplied by -1)

8 + Y = 2Y - 3 OR 8 + Y = -(2Y - 3)

Let's solve the positive case first (first case). Let's start by subtracting 8 from both sides of the equation. Rewrite and now you should have:

Y = 2Y - 11

Now let's subtract 2Y from both sides of the equation. Rewrite and now you should have:

-Y = -11

Divide both sides by negative one to make Y positive. Your final answer should be:

Y = 11

Now let's solve the negative case (second case). Let's start by distributing the negative sign (-1) inside the parentheses. Now you should have:

8 + Y = -2Y + 3

Subtract 8 from both sides of the equation. Rewrite and you should have:

Y = -2Y - 5

Add 2Y to both sides of the equation. Rewrite and you should have:

3Y = -5

To finish off this problem and solve for/isolate Y, divide both sides by 3. Rewrite the equation and your final answer should look like:

Y = -5/3

Substituting -5/3 and 11 will result in a false statement for -5/3 and a true statement for 11, so the answer is Y = 11.

______________________________________________________________

<em>--- Final answers ---</em>

7. The error is that the student did not isolate the absolute value first, and she should have added 3 to both sides of the equation first. The answer is x = 9, -7.

8. The answer is no solution.

9. The answer is Y = 11.

10. The answer is v = -8/3.

______________________________________________________________

*I had to cut question 10 out because I exceeded the limit of characters, sorry! Just for future reference, the limit is 3 problems per question.*

Hope this helped you! Please feel free to comment below if you have any questions (or pm me) and I'll try to get back to you! Good luck on your homework.

★☆★☆★☆ ~laurenercsp6fpli~ ☆★☆★☆★

5 0
4 years ago
If geometry symbol represented as small triangle with three sides. abc geometry congruent symbol represented as two small horizo
n200080 [17]

The value of x in the congruent triangles abc and dec is 1

<h3>How to determine the value x?</h3>

The question implies that the triangles  abc and dec are congruent triangles.

The congruent sides are:

ab = de

bc = ce = 4

ac = cd = 5

The congruent side ab = de implies that:

4x - 1 = x + 2

Collect like terms

4x - x = 2 + 1

Evaluate the like terms

3x = 3

Divide through by 3

x = 1

Hence, the value of x is 1

Read more about congruent triangles at:

brainly.com/question/12413243

#SPJ1

<u>Complete question</u>

Two triangles, abc and cde, share a common vertex c on a grid. in triangle abc, side ab is 4x - 1, side bc is 4, side ac is 5. in triangle cde, side cd is 5, side de is x + 2, side ce is 4. If Δabc ≅ Δdec, what is the value of x? a. x = 8 b. x = 5 c. x = 4 d. x = 1 e. x = 2

3 0
2 years ago
Other questions:
  • Monique Fournier deposited $12,500 into a savings account paying 6.5% annual interest compounded monthly. What amount will she h
    6·1 answer
  • Let r= .12 be the reserve rate. What is the money multiplier?
    12·2 answers
  • Round 248,739 to the nearest hundred
    8·1 answer
  • First to answer gets brainlest! Hurry this is a test.
    14·1 answer
  • How do I solve 5/30 * 100
    11·2 answers
  • 5 friends want to share 2 pizzas. Each friend wants and equal amount. How much pizza does each friend get? Group of answer choic
    7·2 answers
  • Find all the zeros of the polynomial function p(x) = x3 – 5x2 + 33x – 29
    10·1 answer
  • HELP OUT PLEASE!!!!
    13·1 answer
  • Seven times the sum of a number 9 and 2 equals .<br><br><br>WRITE AS AN EQUATION
    10·2 answers
  • The ratio of (1/5 of 245ml) to (0.2 of 0.84l)
    14·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!